首页
学习
活动
专区
圈层
工具
发布
社区首页 >问答首页 >如何从GML文件中提取数据

如何从GML文件中提取数据
EN

Stack Overflow用户
提问于 2020-11-18 17:06:32
回答 1查看 1.1K关注 0票数 2

我有一个文本文件,并希望从其中提取<gml:pos>73664.300 836542.700</gml:pos>。更准确地说,我想从[73664.300 836542.700]标签中得到GPS坐标系pos。该文件包含多个<wfs:member>,每个文件都有一个<gml:pos> (最深层)。

代码语言:javascript
复制
<?xml version='1.0' encoding='UTF-8'?>
<wfs:FeatureCollection xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.opengis.net/wfs/2.0 http://schemas.opengis.net/wfs/2.0/wfs.xsd http://www.opengis.net/gml/3.2 http://schemas.opengis.net/gml/3.2.1/gml.xsd http://www.deegree.org/app https://web.de/feature_descr?SERVICE=WFS&amp;VERSION=2.0.0&amp;REQUEST=DescribeFeatureType&amp;OUTPUTFORMAT=application%2Fgml%2Bxml%3B+version%3D3.2&amp;TYPENAME=app:lsa_data&amp;NAMESPACES=xmlns(app,http%3A%2F%2Fwww.deegree.org%2Fapp)" xmlns:wfs="http://www.opengis.net/wfs/2.0" timeStamp="2020-11-18T15:01:17Z" xmlns:gml="http://www.opengis.net/gml/3.2" numberMatched="unknown" numberReturned="0">
  <!--NOTE: numberReturned attribute should be 'unknown' as well, but this would not validate against the current version of the WFS 2.0 schema (change upcoming). See change request (CR 144): https://portal.opengeospatial.org/files?fact_id=6798.-->
  <wfs:member>
    <app:dat_set xmlns:app="http://www.deegree.org/app" gml:id="app:dat_set_1">
      <app:point>2</app:point>
      <app:art>K         </app:art>
      <app:L_Name>westt / woustest             </app:L_Name>
      <app:geom>
        <!--Inlined geometry 'data_1_APP_GEOM'-->
        <gml:MultiPoint gml:id="data_1_APP_GEOM" srsName="EPSG:25832">
          <gml:pointMember>
            <gml:Point gml:id="GEOMETRY_ad608059-f297-4554-8464-cdde248cb531" srsName="EPSG:25832">
              <gml:pos>73664.300 836542.700</gml:pos>
            </gml:Point>
          </gml:pointMember>
        </gml:MultiPoint>
      </app:geom>
    </app:lsa_pointdata>
  </wfs:member>
  <wfs:member>
    <app:dat_set xmlns:app="http://www.deegree.org/app" gml:id="app:dat_set_2">
      <app:point>3</app:point>
      <app:art>K         </app:art>
      <app:L_Name>route / riztr        </app:L_Name>
      <app:geom>
        <!--Inlined geometry 'data_2_APP_GEOM'-->
        <gml:MultiPoint gml:id="data_2_APP_GEOM" srsName="EPSG:25832">
          <gml:pointMember>
            <gml:Point gml:id="GEOMETRY_440d8630-b674-4768-a5b7-3fab46d9ac8c" srsName="EPSG:25832">
              <gml:pos>74354.900 837456.300</gml:pos>
            </gml:Point>
          </gml:pointMember>
        </gml:MultiPoint>
      </app:geom>
    </app:lsa_pointdata>
  </wfs:member>
  <wfs:member>
    ...
...

我怎么能得到这些gps坐标?

提前谢谢你。

EN

回答 1

Stack Overflow用户

回答已采纳

发布于 2020-11-18 17:25:06

您可以使用lxml和XPATH。

代码语言:javascript
复制
data = b'''\
<?xml version='1.0' encoding='UTF-8'?>
<wfs:FeatureCollection xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.opengis.net/wfs/2.0 http://schemas.opengis.net/wfs/2.0/wfs.xsd http://www.opengis.net/gml/3.2 http://schemas.opengis.net/gml/3.2.1/gml.xsd http://www.deegree.org/app https://web.de/feature_descr?SERVICE=WFS&amp;VERSION=2.0.0&amp;REQUEST=DescribeFeatureType&amp;OUTPUTFORMAT=application%2Fgml%2Bxml%3B+version%3D3.2&amp;TYPENAME=app:lsa_data&amp;NAMESPACES=xmlns(app,http%3A%2F%2Fwww.deegree.org%2Fapp)" xmlns:wfs="http://www.opengis.net/wfs/2.0" timeStamp="2020-11-18T15:01:17Z" xmlns:gml="http://www.opengis.net/gml/3.2" numberMatched="unknown" numberReturned="0">
  <!--NOTE: numberReturned attribute should be 'unknown' as well, but this would not validate against the current version of the WFS 2.0 schema (change upcoming). See change request (CR 144): https://portal.opengeospatial.org/files?fact_id=6798.-->
  <wfs:member>
    <app:dat_set xmlns:app="http://www.deegree.org/app" gml:id="app:dat_set_1">
      <app:point>2</app:point>
      <app:art>K         </app:art>
      <app:L_Name>westt / woustest             </app:L_Name>
      <app:geom>
        <!--Inlined geometry 'data_1_APP_GEOM'-->
        <gml:MultiPoint gml:id="data_1_APP_GEOM" srsName="EPSG:25832">
          <gml:pointMember>
            <gml:Point gml:id="GEOMETRY_ad608059-f297-4554-8464-cdde248cb531" srsName="EPSG:25832">
              <gml:pos>73664.300 836542.700</gml:pos>
            </gml:Point>
          </gml:pointMember>
        </gml:MultiPoint>
      </app:geom>
    </app:dat_set>
  </wfs:member>
  <wfs:member>
    <app:dat_set xmlns:app="http://www.deegree.org/app" gml:id="app:dat_set_2">
      <app:point>3</app:point>
      <app:art>K         </app:art>
      <app:L_Name>route / riztr        </app:L_Name>
      <app:geom>
        <!--Inlined geometry 'data_2_APP_GEOM'-->
        <gml:MultiPoint gml:id="data_2_APP_GEOM" srsName="EPSG:25832">
          <gml:pointMember>
            <gml:Point gml:id="GEOMETRY_440d8630-b674-4768-a5b7-3fab46d9ac8c" srsName="EPSG:25832">
              <gml:pos>74354.900 837456.300</gml:pos>
            </gml:Point>
          </gml:pointMember>
        </gml:MultiPoint>
      </app:geom>
    </app:dat_set>
  </wfs:member>
</wfs:FeatureCollection>
'''

from lxml import etree
from io import BytesIO
f = BytesIO(data)

ns = {"gml": "http://www.opengis.net/gml/3.2"}
tree = etree.parse(f)
for e in tree.findall("//gml:pos", ns):
    print(e.text)
票数 3
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/64897854

复制
相关文章

相似问题

领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档