基于爆炸阵列制作新阵列

Question

我正在尝试创建一个新的数组($names)，它的大小与$years数组相同。我正在循环遍历$year变量，但是很难将$years_names变量加倍(首先用逗号，然后用冒号)，但不确定这是最好的方法。也正因为如此，我无法使用search_array。由于它可能没有每年的数据，所以我希望新的数组在该年的位置上保留一个空值。所以在我的$years_names变量中，我缺少了2010年到2012年的数据，所以索引0-1应该为空，索引8，因为2018年也没有数据。附件或多或少是我试图为我的$names数组获取的东西。谢谢!

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$years = range(2010, 2020);

$data_years = "2010,2011,2012,2013,2014,2015,2016,2017,2018,2019,2020";
$data_names = "Charlie,Lucy,Linus,Pig Pen,Snoopy,Woodstock,Peppermint Patty,Marcie";

$years_names = "2012:Charlie,2013:Lucy,2014:Linus,2015:Pig Pen,2016:Snoopy,2017:Woodstock,2019:Peppermint Patty,2020:Marcie";
$Exploded = explode(',', $years_names);
$names = [];

foreach($Exploded as $i => $item) {
     $names[$i] = explode(':', $item);
    //echo "i= {$i}<br/>";
    //echo "item= {$item}<br/>";
    //echo $names[$i][0] . ':' . $names[$i][1] . "<br/>";
}

Answer 1

你可以做这样的事

$years = range(2010, 2020);
$years_names = "2012:Charlie,2013:Lucy,2014:Linus,2015:Pig Pen,2016:Snoopy,2017:Woodstock,2019:Peppermint Patty,2020:Marcie";

//split `$years_names` at comma
$split_values = explode(',', $years_names);

//convert values to a more usable format
$split_values = array_reduce($split_values, function($return, $item) {
    
    //explode $item (e.g `2012:Charlie`) at the colon symbol
    $explode = explode(':', $item);
    
    //separate year from name as key => value
    $return[$explode[0]] = $explode[1];

    //this return reduces the current iteration of `$split_values` to the key=>value pair
    return $return;
});

$names = [];
foreach($years as $year) {
    
    //set default value as null. If year is not found in next loop, this will remain
    $names[$year] = null;
    
    //check if year exists in $split_values
    if(array_key_exists($year, $split_values)) {
        
        //if it does, set $names[$year] to that value
        $names[$year] = $split_values[$year];
    }
    
}

print_r($names);

输出

Array
(
    [2010] => 
    [2011] => 
    [2012] => Charlie
    [2013] => Lucy
    [2014] => Linus
    [2015] => Pig Pen
    [2016] => Snoopy
    [2017] => Woodstock
    [2018] => 
    [2019] => Peppermint Patty
    [2020] => Marcie
)