Python:转换为JSON格式

Question

Requirement：将纯文本转换为JSON格式

输入：

  data3 =   "{   'type': 'service_account',   'project_id': 'innate-paratext-90872'}"

预期的JSON格式输出：

{
    "type": "service_account",
    "project_id": "innate-paratext-90872"
}

Tried: Method 1

json_str = json.dumps(data3)

输出

"{   'type': 'service_account',   'project_id': 'innate-paratext-90872'}"

方法2:

json_str = json.loads(data3)

误差

json.decoder.JSONDecodeError: Expecting property name enclosed in double quotes: line 1 column 5 (char 4)

编辑1: Mark给出的解决方案很好，但下面举例说明了一些

data3 = "{'type': 'service_account',   'project_id': 'innate-paratext-90872',   'private_key': '-----BEGIN PRIVATE KEY-----\\nMIIEvgIBADANBgkqhkiG9w0BA\\n-----END PRIVATE KEY-----\\n'}",

预期输出：

"private_key": "-----BEGIN PRIVATE KEY-----\nMIIEvgIBADANBgkqhkiG9w0BA\n-----END PRIVATE KEY-----\n",

您的代码输出：(它去掉了“\n”中的"\“)

"private_key": "-----BEGIN PRIVATE KEY-----nMIIEvgIBADANBgkqhkiG9w0BAn-----END PRIVATE KEY-----n",

Answer 1

您的字符串是Python源代码格式，因此可以使用ast.literal_eval将其转换为适合json.dumps的真正Python字典。

>>> s = "{   'type': 'service_account',   'project_id': 'innate-paratext-90872'}"
>>> import ast
>>> d = ast.literal_eval(s)
>>> d
{'type': 'service_account', 'project_id': 'innate-paratext-90872'}
>>> import json
>>> print(json.dumps(d,indent=4))
{
    "type": "service_account",
    "project_id": "innate-paratext-90872"
}