Laravel口香糖还没有工作: error is curl_setopt_array()：不能将输出类型的流表示为STDIO文件*

Question

有人能帮我解决拉勒维尔口香糖的问题吗？

我有一些使用curl的代码，它可以工作。

$ch = curl_init();
curl_setopt($ch, CURLOPT_POSTFIELDS, ['userId' => $appUserId]);
curl_setopt($ch, CURLOPT_URL, $url);
$content = curl_exec($ch);
var_dump($content); // I get a response, response is good.
curl_close($ch);

所有我需要的数据我都得到了很好的回应。简单又好。

然而，我工作的公司在整个应用程序中都使用口香糖，所以当我使用口香糖的时候。

$client = new GuzzleHttp\Client();

try {
    $res = $client->request('POST', $url, [
        'form_params' => [
            'userId' => $appUserId
        ],
        'headers' => ['Content-Type' => 'application/json', 'Accept' => 'application/json'],
        // I have tried every imaginable header.
    ]);

    $result = json_decode($res->getBody());
    echo $res->getBody();
    var_dump($result);
} catch (\GuzzleHttp\Exception\RequestException $e) {
    var_dump('error');
    $guzzleResult = $e->getResponse();
    var_dump($guzzleResult);
}

我因为某种原因而犯了重大错误。

这是错误。

object(GuzzleHttp\Psr7\Response)#317 (6) {
  ["reasonPhrase":"GuzzleHttp\Psr7\Response":private]=>
  string(12) "Unauthorized"
  ["statusCode":"GuzzleHttp\Psr7\Response":private]=>
  int(401)
  ["headers":"GuzzleHttp\Psr7\Response":private]=>
  array(7) {
    ["Host"]=>
    array(1) {
      [0]=>
      string(14) "127.0.0.1:8000"
    }
    ["Date"]=>
    array(2) {
      [0]=>
      string(29) "Wed, 19 Aug 2020 13:39:56 GMT"
      [1]=>
      string(29) "Wed, 19 Aug 2020 13:39:56 GMT"
    }
    ["Connection"]=>
    array(1) {
      [0]=>
      string(5) "close"
    }
    ["X-Powered-By"]=>
    array(1) {
      [0]=>
      string(9) "PHP/7.3.6"
    }
    ["Cache-Control"]=>
    array(1) {
      [0]=>
      string(17) "no-cache, private"
    }
    ["Content-Type"]=>
    array(1) {
      [0]=>
      string(16) "application/json"
    }
    ["Set-Cookie"]=>
    array(2) {
      [0]=>
      string(316) "XSRF-TOKEN=eyJpdiI6ImlPSHczMXRUQ0ZZTUVpRkFPZ052UHc9PSIsInZhbHVlIjoiS0UrYVdkR2ZETWhcL2FLVjRhSVZPM1VxYjVWb3ZoN2dTZlwvWFlNa2hXam1WNVo1NHo3Mk9aZXc5ZFlzYzhlTlNUIiwibWFjIjoiYThiYWVlYjRmOWJmMDgxOWJmZDQzYjg2YWFmZDdjMDFiYzg0ODk5N2FlZTk3ZmI0YjY5MzlmNzYzMGExMThlYSJ9; expires=Wed, 19-Aug-2020 15:39:56 GMT; Max-Age=7200; path=/"
      [1]=>
      string(331) "laravel_session=eyJpdiI6ImpkK2ZtblU3MFpBN3hoSlJ1Wk5Nb2c9PSIsInZhbHVlIjoiVVYxeGtTV09ZZzVoMUcyXC8yaVI0XC9ZbWdYa0hQdkxQZ0xMamE1YzNaZ0NCTjJYbWJSUGl0MWMwRU9rczFUeHdQIiwibWFjIjoiNjJkMGVkYmI0ZDcwMTg4YmZmNjZmYjliYzFjOTI1ODRlN2I4ZTM1MjYyN2U0M2M0YzlmODk0YWVjYzRhNzAyOCJ9; expires=Wed, 19-Aug-2020 15:39:56 GMT; Max-Age=7200; path=/; httponly"
    }
  }
  ["headerNames":"GuzzleHttp\Psr7\Response":private]=>
  array(7) {
    ["host"]=>
    string(4) "Host"
    ["date"]=>
    string(4) "Date"
    ["connection"]=>
    string(10) "Connection"
    ["x-powered-by"]=>
    string(12) "X-Powered-By"
    ["cache-control"]=>
    string(13) "Cache-Control"
    ["content-type"]=>
    string(12) "Content-Type"
    ["set-cookie"]=>
    string(10) "Set-Cookie"
  }
  ["protocol":"GuzzleHttp\Psr7\Response":private]=>
  string(3) "1.1"
  ["stream":"GuzzleHttp\Psr7\Response":private]=>
  object(GuzzleHttp\Psr7\Stream)#315 (7) {
    ["stream":"GuzzleHttp\Psr7\Stream":private]=>
    resource(484) of type (stream)
    ["size":"GuzzleHttp\Psr7\Stream":private]=>
    int(49)
    ["seekable":"GuzzleHttp\Psr7\Stream":private]=>
    bool(true)
    ["readable":"GuzzleHttp\Psr7\Stream":private]=>
    bool(true)
    ["writable":"GuzzleHttp\Psr7\Stream":private]=>
    bool(true)
    ["uri":"GuzzleHttp\Psr7\Stream":private]=>
    string(10) "php://temp"
    ["customMetadata":"GuzzleHttp\Psr7\Stream":private]=>
    array(0) {
    }
  }
} 

如果我将调试设置为true，则得到以下内容

C:\xampp-7\htdocs\website\vendor\guzzlehttp\guzzle\src\Handler\CurlFactory.php：

ErrorException: curl_setopt_array()：无法将输出类型的流表示为STDIO文件*在第59行的文件ErrorException中

我以前用过口香糖，它应该相当简单。

Answer 1

您正在将一些form_params传递给application/json，但是您也将内容类型设置为application/json，并且您的数据不是json格式的。试着

$res = $client->request('POST', $url, [
            'form_params' => [
                'userId' => $appUserId 
            ],
            'headers' => [
               'Accept' => 'application/json'
            ], 
        ]);

此外，为了确保响应体被视为字符串，您应该使用getContents()

$responseData = $res->getBody()->getContents();
$result = json_decode($responseData);

Answer 2

'debug' => fopen('php://stderr', 'w'),

这对我来说很管用

$client->request('POST', $url, [
            'debug' => fopen('php://stderr', 'w'),
            'form_params' => [
                'userId' => $appUserId
            ],
            'headers' => [
                'Content-Type' => 'application/json',
                'Accept' => 'application/json'
            ],
        ]);