TypeError：'>‘函数’和'int‘的实例之间不支持？

Question

**Getting error but confused why everything seems to be in place as it should be?**

，为什么我会得到错误，请解释一下，从上到下，所有的东西基本上都可以工作，直到它到达那个函数，然后，当它给我那个错误时，我正试图找出这个错误，因为我的所有if一个elif和else语句似乎都正常工作，正常工作。

import random
import emoji


def decor(write):
    def wrap():
        print(“Choose a decision!” + “\U0001F604")
        write()
        print("-Testing mode-")
    return wrap()
    
def print_text():
    print("mini project")
decorated = decor(print_text)
print("")



decision = input("please enter decision: " + "")

if decision == ("Right answer"):
    decision = input("I will go to work today!: "+"\U0001F600")
    
    
elif decision ==("Wrong answer"):
    decision = input("Will not go to work today: "+ "\U0001F612")
    
    
else:
    print("Invalid answer try again!")
    

    
if decision == ("Wrong answer"):
     decision = input("But in a bad mood: ")
   
   
elif decision ==("Right answer"):
    decision = input("Your check will come out bigger cause you put in more hours: ")
    print(decision)

    
else:
    print("Invalid answer try again!")

这里是我得到错误的地方

def Decision_maker():
    x = lambda x: x*2 + 1
    if x > 4:
        decision = ("Right answer")
        decision == input("You got a raise!")
        
if decision == ("Wrong answer"):
    decision = input("You got fired: ")
            
        
        

    
Decision_maker()

这里是错误

> Traceback (most recent call last):   File
> "/private/var/mobile/Containers/Shared/AppGroup/3EBFD0C8-D5AE-4513-B2E3-6C38570AE9F0/Pythonista3/Documents/site-packages-3/decision maker.py", line 60, in <module>
>     Decision_maker()   File "/private/var/mobile/Containers/Shared/AppGroup/3EBFD0C8-D5AE-4513-B2E3-6C38570AE9F0/Pythonista3/Documents/site-packages-3/decision maker.py", line 49, in Decision_maker
>     if x > 4: TypeError: '>' not supported between instances of 'function' and 'int

Answer 1

问题在于：

x = lambda x: x*2 + 1
    if x > 4:

您正在传递您的函数，而不是您的函数的结果。相反，试着：

y = lambda x: x*2 + 1
    if y(value) > 4:

其中，值是您想要传递到函数中的任何内容。通过编写"lambda：“，您将创建带有参数"x”的匿名函数。