我对使用jQuery和js非常陌生。我试图使用ajax或get方法输入任何关键字(例如缅因州茧),单击submit,然后能够看到缅因州茧gifs的页面。我所拥有的api代码来自giphy。
function searchGif (){
var input = Document.GetElementById("Search_Form");
input.val();
var input = $('#search').val();
$.get('http://api.giphy.com/v1/gifs/search?q='+input+'&api_key=apikey&limit=20',function(response)
{
$('#img').html("<img src="+response.data[20].images.downsized_large.url+">")
}
)
}
$.get({'http://api.giphy.com/v1/gifs/search?q='+input+'&api_key=apikey&limit=20',function(response)
{
$('#img').html("<img src="+response.data[20].images.downsized_large.url+">")
}
})
}<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8" />
<meta http-equiv="X-UA-Compatible" content="IE=edge" />
<meta name="viewport" content="width=device-width, initial-scale=1.0" />
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/4.5.0/css/bootstrap.min.css">
<link rel="stylesheet" href="styles/style1.css" />
<script src="scripts/script1.js"></script>
<script src="https://code.jquery.com/jquery-3.5.1.slim.min.js" integrity="sha384-DfXdz2htPH0lsSSs5nCTpuj/zy4C+OGpamoFVy38MVBnE+IbbVYUew+OrCXaRkfj" crossorigin="anonymous"></script>
<script src="https://cdn.jsdelivr.net/npm/popper.js@1.16.0/dist/umd/popper.min.js" integrity="sha384-Q6E9RHvbIyZFJoft+2mJbHaEWldlvI9IOYy5n3zV9zzTtmI3UksdQRVvoxMfooAo" crossorigin="anonymous"></script>
<script src="https://stackpath.bootstrapcdn.com/bootstrap/4.5.0/js/bootstrap.min.js" integrity="sha384-OgVRvuATP1z7JjHLkuOU7Xw704+h835Lr+6QL9UvYjZE3Ipu6Tp75j7Bh/kR0JKI" crossorigin="anonymous"></script>
<title>API Test</title>
</head>
<body>
<input id="form-control mr-sm-2" type="search" placeholder="Search">
<button class="btn btn-outline-success my-2 my-sm-0" id="searchgifs" type="submit" onclick="getData()">Search</button>
</action>
<br>
<br>
<script></script>
<!--<div class="inner">
<img src="https://media3.giphy.com/media/hRPoV9O14t3vW/giphy.gif" />
<img src="https://media1.giphy.com/media/GBbkH7cJiVu9y/giphy.gif" />
<img src="https://media1.giphy.com/media/HXpzpXB5syQGQ/giphy.gif" />
<img src="https://media0.giphy.com/media/X9Y9qYPUp1VMQ/giphy.gif" />
<img src="https://media0.giphy.com/media/uuocoePH1mkVy/giphy.gif" />
<img src="https://media0.giphy.com/media/4ml290TZ35zOM/giphy.gif" />
<img src="https://media1.giphy.com/media/8O6EY0lahfInC/giphy.gif" />
<img src="https://media3.giphy.com/media/A7GowSMfBhq6Y/giphy.gif" />
<img src="https://media1.giphy.com/media/dQxSeXsXtf2Lu/giphy.gif" />
<img src="https://media1.giphy.com/media/PzrPi0UVzgYHm/giphy.gif" />
</div>-->
</body>
</html>
发布于 2020-07-14 13:11:29
这里有很多问题:
id属性中有空格,也不能在单个id中有多个值。使用errorDocument.GetElementById()属性。使用class属性。$.get()语法是错误的;还有额外的{}字符是不必要的,导致需要使用AJAX - JS是sensitiveval()方法的情况,这只能在jQuery objectinput缺少您在JS中引用的#search id以获得它的值searchGif(),而不是在HTML的onclick属性中使用的getData()。H 227>H 128也就是说,不要使用onX事件属性,因为它们已经过时,不再有良好的实践了。将事件处理程序不突出地附加到响应中,instead.There可能并不总是21项或更多项,因此移除[20],只使用[0]获取第一项,或者循环遍历它们。综上所述,下面是一个有用的例子:
$('#searchgifs').on('click', function() {
var input = $('#search').val();
$.get('https://api.giphy.com/v1/gifs/search?q=' + input + '&api_key=apikey&limit=20', function(response) {
$('#img').html("<img src=" + response.data[0].images.downsized_large.url + ">")
})
});<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/4.5.0/css/bootstrap.min.css">
<script src="https://code.jquery.com/jquery-3.4.1.min.js"></script>
<script src="https://cdn.jsdelivr.net/npm/popper.js@1.16.0/dist/umd/popper.min.js" integrity="sha384-Q6E9RHvbIyZFJoft+2mJbHaEWldlvI9IOYy5n3zV9zzTtmI3UksdQRVvoxMfooAo" crossorigin="anonymous"></script>
<script src="https://stackpath.bootstrapcdn.com/bootstrap/4.5.0/js/bootstrap.min.js" integrity="sha384-OgVRvuATP1z7JjHLkuOU7Xw704+h835Lr+6QL9UvYjZE3Ipu6Tp75j7Bh/kR0JKI" crossorigin="anonymous"></script>
<input id="search" class="form-control mr-sm-2" type="text" placeholder="Search" value="cat">
<button class="btn btn-outline-success my-2 my-sm-0" id="searchgifs" type="submit">Search</button>
<div id="img"></div>
https://stackoverflow.com/questions/62895597
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