我有一个Image VS Y Double类型的图像(在使用了HIP库中的函数readImageY之后),我想将它转换为Image VS Y Word8。我该怎么做呢?我需要它在这个精度,为下一个函数,我要应用这个。
下面是相关代码的片段:
import Codec.Picture
import Codec.Picture.Types
import Control.Arrow
import Data.Ratio
import Data.Monoid
import Graphics.Image.Processing
import qualified Graphics.Image as I
import Graphics.Image.IO
import Graphics.Image.IO.Formats
import Graphics.Image.Interface.Vector
import qualified Graphics.Image.Interface as Interface
import Data.Word (Word8)
import qualified Data.Matrix as M
import System.FilePath.Posix (splitExtension)
to2DMatrix :: FilePath -> FilePath -> Border(Interface.Pixel I.Y Word8) -> (Int, Int) -> IO ()
to2DMatrix fp fpout bor (dim1, dim2)= do
eimg <- I.readImageY VS fp
let new_res :: Interface.Image VS I.Y Word8
new_res = I.resize Bilinear bor (dim1, dim2) eimg
let rle = twoDToMatrix $ pixelToInt $ toJPImageY8 new_res
let (name, _) = splitExtension fp
writeFile (name ++ ".txt") (show rle)
writeImage fpout rle这是一个错误:
Couldn't match type ‘Double’ with ‘Word8’
Expected type: Interface.Image VS I.Y Word8
Actual type: Interface.Image VS I.Y Double
• In the fourth argument of ‘resize’, namely ‘eimg’
In the expression: resize Bilinear bor (dim1, dim2) eimg
In an equation for ‘new_res’:
new_res = resize Bilinear bor (dim1, dim2) eimg
|
29 | new_res = I.resize Bilinear bor (dim1, dim2) eimg
| ^^^^编辑:是灰度中的像素值,存储为图像类型中的VS向量类型。我遇到的问题是如何获得双打,以便能够转换它们。试图解释/找到一种方式的HIP库这里,但我是新的哈斯克尔,并没有弄清楚。
发布于 2020-06-12 05:25:09
在(HIP)库中的Graphics.Image.Interface中有一个类Graphics.Image.Interface,它允许您将像素精度从/更改为几个精度类型。
下面是更改代码的代码片段:
to2DMatrix :: FilePath -> (Int, Int) -> IO (Maybe (M.Matrix Int))
to2DMatrix fp (dim1, dim2)= do
eimg <- I.readImageY VS fp
let new_res :: Interface.Image VS I.Y Word8
new_res = I.resize Bilinear Edge (dim1, dim2) $ Interface.map conv eimg
let rle = twoDToMatrix $ pixelToInt $ toJPImageY8 new_res
return $ Just (rle)
conv :: Pixel Y Double -> Pixel Y Word8
conv d = toWord8 <$> d<$>是fmap的infix运算符版本。因此,这与:
conv :: Pixel Y Double -> Pixel Y Word8
conv d = fmap toWord8 d将输入图像转换为矩阵的额外详细信息:
pixelToInt从Pixel8类型更改为[[Int]]
pixelToInt :: Image Pixel8 -> [[Int]]
pixelToInt =
map reverse . reverse . snd . pixelFold
(\(lastY, ps:pss) x y p ->
if y == lastY
then (y, (fromIntegral p:ps):pss)
else (y, [fromIntegral p]:ps:pss))
(0,[[]])然后,您可以根据需要使用Data.Matrix从[[Int]]更改为Data.Matrix矩阵类型。
https://stackoverflow.com/questions/62330791
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