如何访问更改的嵌套字典键？

Question

{
    "1": {
        "Furia": "0",
        "Chaos": "1"
    },
    "2": {
        "Furia": "0",
        "Chaos": "2"
    },
    "3": {
        "Furia": "0",
        "Chaos": "3"
    },

然而，假设在另一场比赛中，两支不同的球队正在使用不同的名字，我如何才能获得这些信息。但是总有两支球队。我只知道如何访问Furia和Chaos。

Answer 1

您可以通过使用dict.keys()获取要访问的字典中键的值，并将这些值存储在变量中，并使用这些变量访问所需的值。例如：

dict1={ "item1":1,"item2":2}
>>> dict1.keys()
dict_keys(['item1', 'item2'])
>>> list_of_keys=[x for x in dict1.keys()]
>>> list_of_keys
['item1', 'item2']
>>> dict1[list_of_keys[1]]
2

Answer 2

通过循环它的密钥，我们可以访问它们。

nest_dict = {
    "1": {
        "Furia": "0",
        "Chaos": "1"
    },
    "2": {
        "Furia": "0",
        "Chaos": "2"
    },
    "3": {
        "Furia": "0",
        "Chaos": "3"
    }
}

# Outer loop for getting the keys ['1', '2', '3'] 
for key in nest_dict:
   print(f"{key}:")

   # Inner loop for getting the keys ["Furia", "Chaos"]
   for team in nest_dict[key]:
       print(f"{team} scored: {nest_dict[key][team]}")

   # Printing new line for output readablility
   print()

# Alternate Way
print("Alternate Output\n")
for key in nest_dict:
   print(f"{key}:")

   # Since there will always be two teams.
   team1, team2 = nest_dict[key].keys()

   print(team1, team2)
   print(nest_dict[key][team1], nest_dict[key][team2])

   # Printing new line for output readablility
   print()

输出：

1:
Furia scored: 0
Chaos scored: 1

2:
Furia scored: 0
Chaos scored: 2

3:
Furia scored: 0
Chaos scored: 3

Alternate Output

1:
Furia Chaos
0 1

2:
Furia Chaos
0 2

3:
Furia Chaos
0 3