使用libsox改变音频文件的音高而不改变速度

Question

我开发了一个简单的应用程序，用libsox改变音频文件的音高(使用这个例子)。这是我的密码。它使用两个输入参数-输入文件路径和输出文件路径：

#include <sox.h>
#include <stdlib.h>
#include <stdio.h>
#include <assert.h>
#include <string.h>

int main(int argc, char * argv[])
{
    static sox_format_t * in, * out; /* input and output files */
    sox_effects_chain_t * chain;
    sox_effect_t * e;
    char * args[10];
    sox_signalinfo_t interm_signal; /* @ intermediate points in the chain. */
    sox_encodinginfo_t out_encoding = {
        SOX_ENCODING_SIGN2,
        16,
        0,
        sox_option_default,
        sox_option_default,
        sox_option_default,
        sox_false
    };
    sox_signalinfo_t out_signal = {
        16000,
        1,
        0,
        0,
        NULL
    };

assert(argc == 3);
assert(sox_init() == SOX_SUCCESS);
assert(in = sox_open_read(argv[1], NULL, NULL, NULL));
assert(out = sox_open_write(argv[2], &out_signal, &out_encoding, NULL, NULL, NULL));

chain = sox_create_effects_chain(&in->encoding, &out->encoding);

interm_signal = in->signal; /* NB: deep copy */

e = sox_create_effect(sox_find_effect("input"));
args[0] = (char *)in; 
assert(sox_effect_options(e, 1, args) == SOX_SUCCESS);
assert(sox_add_effect(chain, e, &interm_signal, &in->signal) == SOX_SUCCESS);
free(e);

e = sox_create_effect(sox_find_effect("pitch"));
args[0] = "1000";
assert(sox_effect_options(e, 1, args) == SOX_SUCCESS);
assert(sox_add_effect(chain, e, &interm_signal, &out->signal) == SOX_SUCCESS);
free(e);

e = sox_create_effect(sox_find_effect("output"));
args[0] = (char *)out;
assert(sox_effect_options(e, 1, args) == SOX_SUCCESS);
assert(sox_add_effect(chain, e, &interm_signal, &out->signal) == SOX_SUCCESS);
free(e);

sox_flow_effects(chain, NULL, NULL);

sox_delete_effects_chain(chain);
sox_close(out);
sox_close(in);
sox_quit();

return 0;
}

但是我从上面的代码中得到的结果是一个改变了速度的文件。以下是输入和输出的详细信息：

Input File     : 'input.wav'
Channels       : 1
Sample Rate    : 16000
Precision      : 16-bit
Duration       : 00:00:11.87 = 189921 samples ~ 890.255 CDDA sectors

Input File     : 'output.wav'
Channels       : 1
Sample Rate    : 16000
Precision      : 16-bit
Duration       : 00:00:21.15 = 338401 samples ~ 1586.25 CDDA sectors

另一件事是，sox应用程序运行良好。

sox input.wav output_app.wav pitch 1000

它生成一个与输入具有相同持续时间的文件：

Input File     : 'output_app.wav'
Channels       : 1
Sample Rate    : 16000
Precision      : 16-bit
Duration       : 00:00:11.87 = 189921 samples ~ 890.255 CDDA sectors

这里有谁有同样的问题吗？或者，为了使这种效果正常工作，我还必须向sox_effect提供任何其他选项吗？

Answer 1

libsox的“音调”效应将改变音频采样。如果你注意到“音调”后的样本，你会发现它已经改变了。为了保存具有相同样本的音频文件，您需要在“音调”效果之后添加“速率”效果。如下所示：

#include <sox.h>
#include <stdlib.h>
#include <stdio.h>
#include <assert.h>
#include <string.h>

int main(int argc, char * argv[])
{
    static sox_format_t * in, * out; /* input and output files */
    sox_effects_chain_t * chain;
    sox_effect_t * e;
    char * args[10];
    sox_signalinfo_t interm_signal; /* @ intermediate points in the chain. */
    sox_encodinginfo_t out_encoding = {
        SOX_ENCODING_SIGN2,
        16,
        0,
        sox_option_default,
        sox_option_default,
        sox_option_default,
        sox_false
    };
    sox_signalinfo_t out_signal = {
        16000,
        1,
        0,
        0,
        NULL
    };

    assert(argc == 3);
    assert(sox_init() == SOX_SUCCESS);
    assert(in = sox_open_read(argv[1], NULL, NULL, NULL));
    assert(out = sox_open_write(argv[2], &out_signal, &out_encoding, NULL, NULL, NULL));

    chain = sox_create_effects_chain(&in->encoding, &out->encoding);

    interm_signal = in->signal; /* NB: deep copy */

    e = sox_create_effect(sox_find_effect("input"));
    args[0] = (char *)in; 
    assert(sox_effect_options(e, 1, args) == SOX_SUCCESS);
    assert(sox_add_effect(chain, e, &interm_signal, &in->signal) == SOX_SUCCESS);
    free(e);

    e = sox_create_effect(sox_find_effect("pitch"));
    args[0] = "1000";
    assert(sox_effect_options(e, 1, args) == SOX_SUCCESS);
    assert(sox_add_effect(chain, e, &interm_signal, &out->signal) == SOX_SUCCESS);
    free(e);

    // Note: interm_signal.rate changed now, we need to rate it back

    e = sox_create_effect(sox_find_effect("rate"));
    args[0] = "-m";
    assert(sox_effect_options(e, 1, args) == SOX_SUCCESS);
    assert(sox_add_effect(chain, e, &interm_signal, &out->signal) == SOX_SUCCESS);
    free(e);

    e = sox_create_effect(sox_find_effect("output"));
    args[0] = (char *)out;
    assert(sox_effect_options(e, 1, args) == SOX_SUCCESS);
    assert(sox_add_effect(chain, e, &interm_signal, &out->signal) == SOX_SUCCESS);
    free(e);

    sox_flow_effects(chain, NULL, NULL);

    sox_delete_effects_chain(chain);
    sox_close(out);
    sox_close(in);
    sox_quit();

    return 0;
}

或者，您可以在“比率”之后添加“抖动”效果，以获得更好的效果。

Answer 2

搜索一段时间后，感谢这。我发现，为了保持音频的节奏，必须在音调效应之后将一个速率效应添加到效果链中。