WOE和IV是信用风险分析中的重要概念,用来找出的特征,这些特征与预测是否可能是贷款违约者有关。假设我有一个人有一些变量(可能是年龄、收入、过去的信用评分等等),我需要根据过去的数据预测哪些ppl可能会违约。现在我有1000个变量。在预测贷款违约时,所有变量都不是同等重要的。因此,WOE和IV帮助我找出在任何模型中应该使用的所有变量中的哪个变量。下面是一个示例df和一个用于查找任何df的WOE和IV的通用函数。我对此表示怀疑。
X_train (信用风险分析中的自变量)
Var1 Var2 ............. Var1000
30 Unknown ............. 80000
33 Success ............. 90000
45 Failure ............. 899900y_train (信用风险分析中的因变量,用于表示客户违约与否)
0
1
0
0...and so on代码从数据(WOE和IV)中找到最相关和最重要的变量
import pandas as pd
import numpy as np
import pandas.core.algorithms as algos
from pandas import Series
import scipy.stats.stats as stats
import re
import traceback
import string
max_bin = 20
force_bin = 3
# define a binning function
def mono_bin(Y, X, n = max_bin):
df1 = pd.DataFrame({"X": X, "Y": Y})
justmiss = df1[['X','Y']][df1.X.isnull()]
notmiss = df1[['X','Y']][df1.X.notnull()]
r = 0
while np.abs(r) < 1:
try:
d1 = pd.DataFrame({"X": notmiss.X, "Y": notmiss.Y, "Bucket": pd.qcut(notmiss.X, n)})
d2 = d1.groupby('Bucket', as_index=True)
r, p = stats.spearmanr(d2.mean().X, d2.mean().Y)
n = n - 1
except Exception as e:
n = n - 1
if len(d2) == 1:
n = force_bin
bins = algos.quantile(notmiss.X, np.linspace(0, 1, n))
if len(np.unique(bins)) == 2:
bins = np.insert(bins, 0, 1)
bins[1] = bins[1]-(bins[1]/2)
d1 = pd.DataFrame({"X": notmiss.X, "Y": notmiss.Y, "Bucket": pd.cut(notmiss.X, np.unique(bins),include_lowest=True)})
d2 = d1.groupby('Bucket', as_index=True)
d3 = pd.DataFrame({},index=[])
d3["MIN_VALUE"] = d2.min().X
d3["MAX_VALUE"] = d2.max().X
d3["COUNT"] = d2.count().Y
d3["EVENT"] = d2.sum().Y
d3["NONEVENT"] = d2.count().Y - d2.sum().Y
d3=d3.reset_index(drop=True)
if len(justmiss.index) > 0:
d4 = pd.DataFrame({'MIN_VALUE':np.nan},index=[0])
d4["MAX_VALUE"] = np.nan
d4["COUNT"] = justmiss.count().Y
d4["EVENT"] = justmiss.sum().Y
d4["NONEVENT"] = justmiss.count().Y - justmiss.sum().Y
d3 = d3.append(d4,ignore_index=True)
d3["EVENT_RATE"] = d3.EVENT/d3.COUNT
d3["NON_EVENT_RATE"] = d3.NONEVENT/d3.COUNT
d3["DIST_EVENT"] = d3.EVENT/d3.sum().EVENT
d3["DIST_NON_EVENT"] = d3.NONEVENT/d3.sum().NONEVENT
d3["WOE"] = np.log(d3.DIST_EVENT/d3.DIST_NON_EVENT)
d3["IV"] = (d3.DIST_EVENT-d3.DIST_NON_EVENT)*np.log(d3.DIST_EVENT/d3.DIST_NON_EVENT)
d3["VAR_NAME"] = "VAR"
d3 = d3[['VAR_NAME','MIN_VALUE', 'MAX_VALUE', 'COUNT', 'EVENT', 'EVENT_RATE', 'NONEVENT', 'NON_EVENT_RATE', 'DIST_EVENT','DIST_NON_EVENT','WOE', 'IV']]
d3 = d3.replace([np.inf, -np.inf], 0)
d3.IV = d3.IV.sum()
return(d3)
def char_bin(Y, X):
df1 = pd.DataFrame({"X": X, "Y": Y})
justmiss = df1[['X','Y']][df1.X.isnull()]
notmiss = df1[['X','Y']][df1.X.notnull()]
df2 = notmiss.groupby('X',as_index=True)
d3 = pd.DataFrame({},index=[])
d3["COUNT"] = df2.count().Y
d3["MIN_VALUE"] = df2.sum().Y.index
d3["MAX_VALUE"] = d3["MIN_VALUE"]
d3["EVENT"] = df2.sum().Y
d3["NONEVENT"] = df2.count().Y - df2.sum().Y
if len(justmiss.index) > 0:
d4 = pd.DataFrame({'MIN_VALUE':np.nan},index=[0])
d4["MAX_VALUE"] = np.nan
d4["COUNT"] = justmiss.count().Y
d4["EVENT"] = justmiss.sum().Y
d4["NONEVENT"] = justmiss.count().Y - justmiss.sum().Y
d3 = d3.append(d4,ignore_index=True)
d3["EVENT_RATE"] = d3.EVENT/d3.COUNT
d3["NON_EVENT_RATE"] = d3.NONEVENT/d3.COUNT
d3["DIST_EVENT"] = d3.EVENT/d3.sum().EVENT
d3["DIST_NON_EVENT"] = d3.NONEVENT/d3.sum().NONEVENT
d3["WOE"] = np.log(d3.DIST_EVENT/d3.DIST_NON_EVENT)
d3["IV"] = (d3.DIST_EVENT-d3.DIST_NON_EVENT)*np.log(d3.DIST_EVENT/d3.DIST_NON_EVENT)
d3["VAR_NAME"] = "VAR"
d3 = d3[['VAR_NAME','MIN_VALUE', 'MAX_VALUE', 'COUNT', 'EVENT', 'EVENT_RATE', 'NONEVENT', 'NON_EVENT_RATE', 'DIST_EVENT','DIST_NON_EVENT','WOE', 'IV']]
d3 = d3.replace([np.inf, -np.inf], 0)
d3.IV = d3.IV.sum()
d3 = d3.reset_index(drop=True)
return(d3)
def data_vars(df1, target):
stack = traceback.extract_stack()
filename, lineno, function_name, code = stack[-2]
vars_name = re.compile(r'\((.*?)\).*$').search(code).groups()[0]
final = (re.findall(r"[\w']+", vars_name))[-1]
x = df1.dtypes.index
count = -1
for i in x:
if i.upper() not in (final.upper()):
if np.issubdtype(df1[i], np.number) and len(Series.unique(df1[i])) > 2:
conv = mono_bin(target, df1[i])
conv["VAR_NAME"] = i
count = count + 1
else:
conv = char_bin(target, df1[i])
conv["VAR_NAME"] = i
count = count + 1
if count == 0:
iv_df = conv
else:
iv_df = iv_df.append(conv,ignore_index=True)
iv = pd.DataFrame({'IV':iv_df.groupby('VAR_NAME').IV.max()})
iv = iv.reset_index()
return(iv_df,iv)调用函数
final_iv, IV = data_vars(X_train, y_train)输出
VAR_NAME MIN_VALUE MAX_VALUE COUNT EVENT EVENT_RATE NONEVENT NON_EVENT_RATE DIST_EVENT DIST_NON_EVENT WOE IV
0 Var1 19 39 2290 259 0.113100 2031 0.886900 0.497121 0.50775 -0.021156 0.000452
1 Var1 40 87 2231 262 0.117436 1969 0.882564 0.502879 0.49225 0.021363 0.000452
64 Var2 failure failure 490 63 0.128571 427 0.871429 0.120921 0.10675 0.124650 0.461890
65 Var2 other other 197 38 0.192893 159 0.807107 0.072937 0.03975 0.606982 0.461890
66 Var2 success success 129 83 0.643411 46 0.356589 0.159309 0.01150 2.628499 0.461890
67 Var2 unknown unknown 3705 337 0.090958 3368 0.909042 0.646833 0.84200 -0.263692 0.461890等等..。
如果您看到相同变量Var1有2个值,Var2变量有4个值。我无法理解同一变量的多行的含义。data_vars试图做的这个函数是什么?
发布于 2020-03-17 15:23:55
这些结果是结合在一起的,可能是在假设某些特征在它们的分布中可能有不同的灾祸/四级分数的情况下。例如,Var1的19,39分与40,87分是不同的。对于Var2这样的分类变量来说,这种绑定是否有意义是另一回事。
https://stackoverflow.com/questions/60723737
复制相似问题