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社区首页 >问答首页 >如何防止gmail线程返回

如何防止gmail线程返回
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Stack Overflow用户
提问于 2020-03-15 21:56:19
回答 1查看 69关注 0票数 0

我有这个功能,我每小时运行一次。它检查收件箱中是否有邮件列表。然后,它重新格式化它们,保存附件,并将它们转发到另一个电子邮件地址,然后表面上丢弃处理过的消息。效果很好,除了..。

我最近遇到了一条不会死的线索。它有50多个回复,当新的回复以相同的主题行出现时,线程中所有已经处理过的旧消息都会再次被处理。因此,我发送的邮箱呈指数增长,收件人的电子邮件收件箱也是如此。我不确定是否只是简单地没有有效地删除发送的消息,或者是否有其他方法来标识线程中已经处理过的消息,这样当更多消息被添加到线程中时,它们就不会再被处理了。我不知道这是应用程序脚本问题还是gmail问题。

这是我的密码:

代码语言:javascript
复制
function processPMFMail(){
  var threads = GmailApp.getInboxThreads();
  var message = GmailApp.getMessagesForThreads(threads); 
  for(var i = 0; i < message.length; i++) {
    for(var j = 0; j < message[i].length; j++) {
      var from = message[i][j].getFrom();
      var to = message[i][j].getTo();
      var cc = message[i][j].getCc();
      var bcc = message[i][j].getBcc();
      var fields = {to, cc, bcc};
                    //Logger.log(to);

                    if (
                    [to,cc,bcc].some(field =>
                    ["EMAIL-1","EMAIL-2"].some(email => field.includes(email))
                    )
                    ) {
                    var subject = cleanSubject(message[i][j]);
                    if (subject == "DoNotPost") {
                    Logger.log("Email not for posting - " + cleanSubject(message[i][j]));
                    message[i][j].moveToTrash();
                   } else{
                    var from = parseEmailName(message[i][j]);
                    var body = message[i][j].getPlainBody();
                    var hBody = message[i][j].getBody();
                    var attachment = saveAttachments(message[i][j]);
                    var opening = "<br>From: " + from + "<br> Sent: "+ Utilities.formatDate(message[i][j].getDate(), "US/Eastern", "M/d/yy @ h:mm aaa") + "<br><br>" + attachment;
                    if (hBody.indexOf("</body>")>-1) {
                    hBody = removeForwards (hBody);
                    hBody = hBody.replace("</body>",opening + "</body>").trim();
                   } else{
                    hBody = hBody + opening;
                   }
                    Logger.log(subject + opening);
                    //send the message
                    GmailApp.sendEmail("EMAIL-3", subject , opening + body , 
                    {htmlBody: hBody, 
                    name: from
                   })  
    }  // end of processed messages
    //move the message to the trash
    message[i][j].moveToTrash();
  } 
  else {Logger.log("No Messages to forward")}
}
}

}

任何指南针都很感激。

-DH

EN

回答 1

Stack Overflow用户

回答已采纳

发布于 2020-03-16 11:30:27

因此,如果我正确理解,您将从一个线程中得到所有的消息。

但是最后,这是预期的,因为您首先获得GmailThread,然后检查线程中的每个GmailMessage。即使您已经检查并删除了它,它也是线程的一部分,在使用getMessagesForThreads()时得到它是正常的。

我建议在每条消息中(在for嵌套循环中)使用isInTrash(),以检查是否已经将该消息移动到垃圾中。

就像这样:

代码语言:javascript
复制
function processPMFMail() {
    var threads = GmailApp.getInboxThreads();
    var message = GmailApp.getMessagesForThreads(threads);
    for (var i = 0; i < message.length; i++) {
        for (var j = 0; j < message[i].length; j++) {
            if (!message[i][j].isInTrash()) {
                var from = message[i][j].getFrom();
                var to = message[i][j].getTo();
                var cc = message[i][j].getCc();
                var bcc = message[i][j].getBcc();
                var from = message[i][j].getFrom();
                var fields = { to, cc, bcc };
                //Logger.log(to);

                if (
                    [to, cc, bcc].some(field =>
                        ["EMAIL-1", "EMAIL-2"].some(email => field.includes(email))
                    )
                ) {
                    var subject = cleanSubject(message[i][j]);
                    if (subject == "DoNotPost") {
                        Logger.log("Email not for posting - " + cleanSubject(message[i][j]));
                        message[i][j].moveToTrash();
                    } else {
                        var from = parseEmailName(message[i][j]);
                        var body = message[i][j].getPlainBody();
                        var hBody = message[i][j].getBody();
                        var attachment = saveAttachments(message[i][j]);
                        var opening = "<br>From: " + from + "<br> Sent: " + Utilities.formatDate(message[i][j].getDate(), "US/Eastern", "M/d/yy @ h:mm aaa") + "<br><br>" + attachment;
                        if (hBody.indexOf("</body>") > -1) {
                            hBody = removeForwards(hBody);
                            hBody = hBody.replace("</body>", opening + "</body>").trim();
                        } else {
                            hBody = hBody + opening;
                        }
                        Logger.log(subject + opening);
                        //send the message
                        GmailApp.sendEmail("EMAIL-3", subject, opening + body,
                            {
                                htmlBody: hBody,
                                name: from
                            })
                    }  // end of processed messages
                    //move the message to the trash
                    message[i][j].moveToTrash();
                }
                else { Logger.log("No Messages to forward") }
            }
        }
    }

}
票数 2
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/60698062

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