我有以前的卡夫卡知识,我一直在玩Nats.io,这似乎是一个非常可靠的消息选择。
特别是,我对详细记录在案的请求/应答机制很感兴趣,但我在用Jnats驱动程序正确实现它时遇到了困难。
这是我的连接器:
// Single server nats connection
@PostConstruct
public void connect() throws ExternalServiceUnavailableException {
Options options = new Options.Builder()
.server(connectionString)
.maxReconnects(20)
.reconnectWait(Duration.ofSeconds(5))
.connectionTimeout(Duration.ofSeconds(5))
.connectionListener((conn, type) -> {
if (type == ConnectionListener.Events.CONNECTED) {
LOG.info("Connected to Nats Server");
} else if (type == ConnectionListener.Events.RECONNECTED) {
LOG.info("Reconnected to Nats Server");
} else if (type == ConnectionListener.Events.DISCONNECTED) {
LOG.error("Disconnected to Nats Server, reconnect attempt in seconds");
} else if (type == ConnectionListener.Events.CLOSED) {
LOG.info("Closed connection with Nats Server");
}
})
.build();
try {
connection = Nats.connect(options);
} catch (Exception e) {
LOG.error("Unable to connect to Nats Server");
throw new ExternalServiceUnavailableException(ExternalServiceUnavailableException.Service.NATS);
}
}这是请求方法(用于测试的等待时间非常长):
public Optional<String> asyncRequest(String topic, String message) throws ExternalServiceUnavailableException {
Future<Message> reply = natsConnector.getConnection().request(topic, message.getBytes());
try {
Message msg = reply.get(10L, TimeUnit.SECONDS);
LOG.info(new String(msg.getData()));
return Optional.of(new String(msg.getData(), StandardCharsets.UTF_8));
} catch (InterruptedException | ExecutionException | TimeoutException e) {
e.printStackTrace();
LOG.error("Unable to retrieve response for the sent request: " + message);
throw new ExternalServiceUnavailableException(ExternalServiceUnavailableException.Service.NATS);
}
}这是具有应答机制的响应处理程序:
@PostConstruct
private void init() {
Dispatcher dispatcher = natsConnector.getConnection().createDispatcher(message -> {
});
Subscription assetsInfo = dispatcher.subscribe("assets-info", message -> {
JSONObject requestMessage = new JSONObject(new String(message.getData(), StandardCharsets.UTF_8));
if (requestMessage.getString("requestType").equals("stock-status")) {
if (requestMessage.getString("of").equals("all")) {
JSONObject response = assetQuery.retrieveYesterdayStockStatus();
LOG.info("response ready");
natsOperation.publishEvent("assets-info", response);
LOG.info("message sent");
}
}
});
}我的两个独立服务通过一个被篡改的Nats.io进行通信,并且我可以通过Nats客户端正确地检查两个服务是否就同一主题发送了消息。
不幸的是,当调用asyncRequest函数时,"Requestor“并不完全处理答复,即使在reply.get(...)中等待很高。
当我试图在调试模式下计算reply对象时,它中没有任何数据,并显示了一个TimeoutException。
在msg.getData(),程序崩溃。
你们有什么线索给我吗?谢谢!
发布于 2020-03-11 17:15:44
您应该更改您的“应答器”代码,以便从原始消息发布到replyTo主题。
@PostConstruct
private void init() {
Dispatcher dispatcher = natsConnector.getConnection().createDispatcher(message -> {
});
Subscription assetsInfo = dispatcher.subscribe("assets-info", message -> {
JSONObject requestMessage = new JSONObject(new String(message.getData(), StandardCharsets.UTF_8));
if (requestMessage.getString("requestType").equals("stock-status")) {
if (requestMessage.getString("of").equals("all")) {
JSONObject response = assetQuery.retrieveYesterdayStockStatus();
LOG.info("response ready");
//See Change Here
natsOperation.publish(message.getReplyTo(), response);
LOG.info("message sent");
}
}
});
}请求应答机制正在寻找生成的replyTo主题上的单个响应。
https://stackoverflow.com/questions/60617016
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