@SqlResultSetMapping用法导致架构验证问题

Question

为了统计目的，我必须提取数据。我创建了一个本机查询，并使用@SqlResultSetMapping将结果集映射到一个对象。Hibernate需要将这个类(精化)声明为@Entity，但不是一个表，而且我不想要一个表，因为我只需要在需要时动态提取数据。

代码运行良好，但gitlab管道在验证过程中失败。

schemaManagementException: Schema-validation: missing table [elaboration].

到目前为止，我的代码如下：

    SqlResultSetMapping(name="ValueMapping",
                     classes={
                       @ConstructorResult(
                         targetClass=Elaboration.class,
                         columns={
                           @ColumnResult(name="areadesc", type=String.class),
                           @ColumnResult(name="subsectordesc", type=String.class),
                           @ColumnResult(name="eurovalue", type=BigDecimal.class),
                           @ColumnResult(name="eurotch", type=BigDecimal.class),
                         }
                       )
                     })
    @Entity 
    public class Elaboration{
      @Id
      private Long id;
      private String areadesc;
      private String subsectordesc;
      private Integer dossiercount;
      private BigDecimal eurovalue;
      private BigDecimal eurotch; 

    ....

以及自定义查询：

        String statisticValueQuery = "select  a.mdescr as areadesc, s.mdescr as subsectordesc, sum(euro_value) as eurovalue, 
    sum(euro_value_tch) as eurotch " +
                                   "from dossier d " +
                                   "join dossier_document dd on d.id = dd.dossier_id " +
                                   "join dossier_country dc on d.id = dc.dossier_id " +
                                   "join country c on dc.country_id = c.id " +
                                   "join area a on c.area_id = a.id " +
                                   "join dossier_subsector ds on d.id = ds.dossier_id " +
                                   "join subsector s on ds.subsector_id = s.id " +
                                   "where dd.document_id = :document  " +
                                   "and d.submission_date >= :startdate  and d.submission_date <= :enddate " +
                                   "group by s.id, a.id;";

      public List<Elaboration> getValueElaboration(ElaborationRequestDTO elaborationRequestDTO){

        Query resultMapping = em.createNativeQuery(statisticValueQuery, "ValueMapping");
        resultMapping.setParameter("startdate", elaborationRequestDTO.getElaborateFromEquals());
        resultMapping.setParameter("enddate", elaborationRequestDTO.getElaborateToEquals());
        resultMapping.setParameter("document", elaborationRequestDTO.getDocumentIdEquals());
        return resultMapping.getResultList();

是否有办法通过验证测试？谢谢

Answer 1

这是错误的说法。

Hibernate需要声明这个类(精化)为@Entity

您应该将@SqlResultSetMapping声明置于某些@Entity之上，但它可以是与Elaboration无关的其他实体。

@SqlResultSetMapping(name="ValueMapping",
                 classes={
                   @ConstructorResult(
                     targetClass=Elaboration.class,
                     columns={
                       @ColumnResult(name="areadesc", type=String.class),
                       @ColumnResult(name="subsectordesc", type=String.class),
                       @ColumnResult(name="eurovalue", type=BigDecimal.class),
                       @ColumnResult(name="eurotch", type=BigDecimal.class),
                     }
                   )
                 })
@Entity 
public class SomeEntity {

}

如果Elaboration不是一个实体，则不应该对其进行注释。