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当存在JsonSerializer<Date>()时,JsonSerializer<Timestamp>()不适用于JsonSerializer<Timestamp>字段
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Stack Overflow用户
提问于 2019-11-25 07:48:26
回答 1查看 924关注 0票数 1

在我的java应用程序中,我使用了JsonSerializer和JsonSerializer()来序列化java.util.Date和java.sql.Timestamp字段respectively.But,问题是当我使用gson将对象解析为json字符串时,java.util.Date字段使用JsonSerializer()序列化程序而不是JsonSerializer。下面是我的密码。

代码语言:javascript
复制
Gson gson;
GsonBuilder builder;
SimpleDateFormat dtf=new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
SimpleDateFormat dtfDate=new SimpleDateFormat("yyyy-MM-dd");
builder = new GsonBuilder();

builder.registerTypeAdapter(Timestamp.class, new JsonSerializer<Timestamp>() {
    @Override
    public JsonElement serialize(Timestamp src, Type typeOfSrc, JsonSerializationContext context) {
        dtf.setTimeZone(TimeZone.getTimeZone("UTC"));
        String jsDate = dtf.format(src);
        System.out.println("Timestamp : src - "+src+" jsDate - "+jsDate+" typeOfSrc - "+typeOfSrc);
        return new JsonPrimitive(jsDate);
    }
});
builder.registerTypeAdapter(Date.class, new JsonSerializer<Date>() {
    @Override
    public JsonElement serialize(Date src, Type typeOfSrc, JsonSerializationContext context) {
        String jsDate = dtfDate.format(src);
        System.out.println("Date : src - "+src+" jsDate - "+jsDate+" typeOfSrc - "+typeOfSrc);
        return new JsonPrimitive(jsDate);
    }
});
gson = builder.create();
PersonSubstitution  personSubstitution = loopDao.getPersonSubstitution(Integer.parseInt(deptId),date);
String jsonAccts = gson.toJson(personSubstitution, PersonSubstitution.class);

PersonSubstitution.class:

代码语言:javascript
复制
import javax.persistence.*;
import java.io.Serializable;
import java.sql.Timestamp;
import java.util.Date;
import java.util.Objects;


@Entity
@Table(name = "person_substitution")
public class PersonSubstitution implements Serializable {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "id")
    private int id;

    @JoinColumn(name = "dept_id", referencedColumnName = "id", nullable = false)
    @ManyToOne(optional = false)
    private Departments deptId;

    @Column(name = "date")
    private Date date;

    @JoinColumn(name = "staff_id", referencedColumnName = "person_id", nullable = false)
    @OneToOne(optional = false)
    private Person staffId;

    @Column(name = "created_on")
    private Timestamp createdOn;

    public PersonSubstitution() {

    }

    public PersonSubstitution(int id, Departments deptId, Date date, Person staffId, Timestamp createdOn) {
        this.id = id;
        this.deptId = deptId;
        this.date = date;
        this.staffId = staffId;
        this.createdOn = createdOn;
    }

    public int getId() {
        return id;
    }

    public void setId(int id) {
        this.id = id;
    }

    public Departments getDeptId() {
        return deptId;
    }

    public void setDeptId(Departments deptId) {
        this.deptId = deptId;
    }

    public Date getDate() {
        return date;
    }

    public void setDate(Date date) {
        this.date = date;
    }

    public Person getStaffId() {
        return staffId;
    }

    public void setStaffId(Person staffId) {
        this.staffId = staffId;
    }

    public Timestamp getCreatedOn() {
        return createdOn;
    }

    public void setCreatedOn(Timestamp createdOn) {
        this.createdOn = createdOn;
    }
}

我将System.out.println()放在序列化器和只有时间戳支架中,如下所示:

代码语言:javascript
复制
Timestamp : src - 2019-11-28 00:00:00.0 jsDate - 2019-11-27 18:30:00 typeOfSrc - class java.sql.Timestamp
Timestamp : src - 2019-11-25 12:08:14.0 jsDate - 2019-11-25 06:38:14 typeOfSrc - class java.sql.Timestamp

那么,日期字段是否可以使用builder.registerTypeAdapter(Date.class, new JsonSerializer<Date>() {...}而不是builder.registerTypeAdapter(Date.class, new JsonSerializer<Timestamp>() {...}呢??

EN

回答 1

Stack Overflow用户

回答已采纳

发布于 2019-11-25 10:40:57

它是这样工作的,因为在运行时,datecreatedOnTimestamp。您需要将给定的序列化程序分配给字段。因此,您需要创建一个自定义序列化程序:

代码语言:javascript
复制
class DateJsonSerializer implements JsonSerializer<Date> {

    private final ThreadLocal<SimpleDateFormat> formatter = ThreadLocal.withInitial(() -> new SimpleDateFormat("yyyy-MM-dd"));

    @Override
    public JsonElement serialize(Date src, Type typeOfSrc, JsonSerializationContext context) {
        String formatted = formatter.get().format(src);

        return new JsonPrimitive(formatted);
    }
}

Timestamp序列化程序:

代码语言:javascript
复制
class TimestampJsonSerializer implements JsonSerializer<Timestamp> {

    private final ThreadLocal<SimpleDateFormat> formatter = ThreadLocal.withInitial(() -> {
        SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
        dateFormat.setTimeZone(TimeZone.getTimeZone("UTC"));
        return dateFormat;
    });

    @Override
    public JsonElement serialize(Timestamp src, Type typeOfSrc, JsonSerializationContext context) {
        String formatted = formatter.get().format(src);
        return new JsonPrimitive(formatted);
    }
}

并将其声明为Date字段:

代码语言:javascript
复制
@JsonAdapter(DateJsonSerializer.class)
private Date date;

您仍然可以将其注册为Date类的全局序列化程序:

代码语言:javascript
复制
Gson gson = new GsonBuilder()
        .setPrettyPrinting()
        .registerTypeAdapter(Timestamp.class, new TimestampJsonSerializer())
        .registerTypeAdapter(Date.class, new DateJsonSerializer())
        .create();

注意到:我使用ThreadLocal是因为SimpleDateFormat不是线程安全的。

票数 1
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/59027234

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