要求:按下guizero上的一个按钮,首先设置一个文本值,然后执行一个函数(这里是一个简单的time.sleep();最初是一个子进程);在执行该函数之后,应该显示一个结果文本;
#!/usr/bin/python3
# -*- coding: utf-8 -*-
from guizero import App, PushButton, Text
import subprocess
import time
# Action you would like to perform
def counter0():
global s0
text0.value = int(text0.value) + 1 # works
text1.value = s0 # works
def counter1():
global s0
text1.value = s0 # display a status value - but does not (!)
time.sleep(1) # originally a subprocess is called here; works
text1.value = "ready" # only diplays this after a delay
s0="start something after pressing butt1"
app = App("Hello world", layout="grid")
text0 = Text(app, text="1", align="left", grid=[0,1])
text1 = Text(app, text=s0, align="left",grid=[0,8] )
butt1 = PushButton(app, text="Button", command=counter1, align="left", grid=[0,2])
text0.repeat(10000, counter0) # Schedule call to counter() every 1000ms
app.display()很可能我不明白吉泽罗背后的想法。对如何管理这些需求有什么想法吗?
发布于 2019-11-24 14:47:13
如果我正确理解你的问题,你的具体问题是:
text1.value = s0 # display a status value - but does not (!)这不起作用,因为guizero框架同步执行函数:在函数返回之前,不执行其他代码(包括更新显示的代码)。
如果你想:
在使用subprocess
之后
然后,您将需要重写您的逻辑,这样您的应用程序就不会等待“抗衡1”完成。异步运行代码的一个选项是在一个单独的线程中运行它。例如:
from guizero import App, PushButton, Text
import threading
import time
# Action you would like to perform
def counter0():
global s0
text0.value = int(text0.value) + 1 # works
text1.value = s0 # works
def run_command():
time.sleep(1) # originally a subprocess is called here; works
text1.value = "ready" # only diplays this after a delay
def counter1():
global s0
text1.value = "Running command..."
threading.Thread(target=run_command).start()
s0 = "start something after pressing butt1"
app = App("Hello world", layout="grid")
text0 = Text(app, text="1", align="left", grid=[0, 1])
text1 = Text(app, text=s0, align="left", grid=[0, 8])
butt1 = PushButton(app, text="Button", command=counter1,
align="left", grid=[0, 2])
text0.repeat(10000, counter0)
app.display()运行上述代码将为您提供以下行为:

https://stackoverflow.com/questions/59018383
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