在嵌套字典中查找特定键的值

Question

我有一本嵌套字典

 customer_order = {order0 
{'Orientation': what_orientation, 'Size': what_size, 'sizecost': size_cost, 
 'eyelets': how_many_eyelets, 'eyeletcost': eyelet_cost, 'material': what_material,
 'materialcost': material_cost, 'ropes': need_ropes, 'ropecost': rope_cost, 
 'image': need_image, 'imagecost': 0, 'wording': what_wording, 'wordcost':word_cost}

order1{'Orientation': what_orientation, 'Size': what_size, 'sizecost': size_cost, 
 'eyelets': how_many_eyelets, 'eyeletcost': eyelet_cost, 'material': what_material, 
 'materialcost': material_cost, 'ropes': need_ropes, 'ropecost': rope_cost, 
'image': need_image, 'imagecost': 0, 'wording': what_wording, 'wordcost':word_cost}}

我需要做的是获取以下键的值

sizecost
eyeletcost
materialcost
ropecost
wordcost

如何循环获得这些值并将它们添加到正在运行的总数中？

谢谢

我尝试了下面的代码，但是得到了错误

for key, value in cust_details:

ValueError:太多的值无法解包(预期的2)

对于cust_order，cust_details在customer_order.items()：print(“\n nOrder："，cust_order)中表示key，value in cust_details: if (key == "sizecost")：+=值

        if (key == "eyeletcost"):
            totalcosts += value

        if (key == "materialcost"):
            totalcosts += value

        if (key == "ropecost"):
            totalcosts += value

        if (key == "wordcost"):
            totalcosts += value

总成本+=值

Answer 1

您可以使用recurssion

def look(key,d,val = None):
    if val is None:
        val = []
    if key in d.keys():
       val.append(d.get(key))
    else:
        for i,j in d.items():
            if isinstance(j,dict):
                look(key,j,val)
    return val

现在尝试调用：look("sizecost", customer_order )