绘制扫雷游戏板有困难

Question

我正在使用C++构建一个扫雷游戏。现在，我无法在输入文件中读取内容，并使用内容来构建我的游戏板，如下所示：GameBoard

到目前为止，这就是我所拥有的：

main.cpp

#include <iostream>
#include <string>

#include "UI.hpp"
#include "drawboard.hpp"

int main()
{

    UI start;
    start.Gameprompt();        

    int drawgame[4][4] = {{' ',' ',' ',' '},{' ',' ',' ',' '},{' ',' ',' ',' '},{' ',' ',' ',' '}};
    drawBoard(drawgame);


    return 0;
}

UI.hpp

#ifndef UI_HPP
#define UI_HPP


#include <iostream>
#include <fstream>
#include <string>

class UI
{

    private:
            std::string filename;


    public:
            void GamePrompt();


};


#endif

UI.cpp

#include <iostream>
#include <fstream>
#include <string>


#include "UI.hpp"


void UI::GamePrompt()
{
    std::ifstream inFS;

    while (!inFS.is_open())
    {
            std::cout << "Please enter a file name with the minefield information: " << std::endl;
            std::cin >> filename;
            inFS.open(filename.c_str());
    }


}

drawboard.hpp

#ifndef DRAWBOARD_HPP
#define DRAWBOARD_HPP

class drawBoard
{

    private:
            int board[4][4];

    public:
            drawBoard(int board[][4]);


};

#endif

drawboard.cpp

#include "drawboard.hpp"
#include<iostream>

drawBoard::drawBoard(int board[][4])
{

    std::cout << " 0 1 2 3 " << std::endl;
    for(int i = 0; i < 4; i++)
    {

            std::cout << " +---+---+---+---+" << std::endl;
            std::cout << i + 1;

            for(int j = 0; j < 4; j++)
            {

                    std::cout << " | " << board[i][j];

            }

            std::cout << " | " << std::endl;

    }

    std::cout << " +---+---+---+---+" << std::endl;

}

以下是我现在所收到的错误：

main.cpp: In function ‘int main()’:
main.cpp:18:20: error: conflicting declaration ‘drawBoard drawgame’
drawBoard(drawgame);
                ^
main.cpp:16:6: error: ‘drawgame’ has a previous declaration as ‘int drawgame [4][4]’
int drawgame[4][4] = {{' ',' ',' ',' '},{' ',' ',' ',' '},{' ',' ',' ',' '},{' ',' ',' ',' '}};
  ^
main.cpp:16:6: warning: unused variable ‘drawgame’ [-Wunused-variable]

预先感谢您的帮助

Answer 1

这个错误其实有点模糊..。

当编译器看到行时

drawBoard(drawgame);

它认为您正在将变量drawgame定义为一个drawBoard实例，也就是说，它认为您正在执行的是

drawBoard drawgame;

解决方案很简单，像通常那样定义变量，然后将数组传递给构造函数，如下所示

drawBoard board(drawgame);

或者，正如评论中提到的，您可以这样做

drawBoard{drawgame};

但这只会创建一个将立即销毁的临时drawBoard对象。