用汤在两个元素之间获取元素

Question

我有以下HTML代码：

<div class="info">
    <div class="left-wrap"><span class="date">DATE-1</span></div>
</div>

<div class="clients-list">
        <div>
            <span class="client" >client1</span>
            <span class="client" >client2</span>
            <span class="client" >client3</span>
        </div>
    </div>

<div class="info">
    <div class="left-wrap"><span class="date" >DATE-2</span></div>
</div>
<div class="clients-list">
        <div>
            <span class="client" >client4</span>
            <span class="client" >client5</span>
        </div>
</div>

我想获得与每一次约会相关的数据，我做了以下工作：

date = []
clients = []
for item in soup.find_all(class_='date'):
    date.append(item.get_text().strip())
for item in soup.find_all(class_='client'): 
    clients.append(item.get_text().strip())
print date
print clients

最后，我得到了包含"date1“和"date2”的日期列表，以及包含clients1到clients5的客户端列表。

我的问题是，我无法用日期映射客户端，例如client1、client2和client3以及与date1相关的客户端，但我没有找到任何方法来知道每个日期下将有多少客户端。

Answer 1

尝试this.Use find_next()查找下一个div标记，然后查找find_all() span标记。

from bs4 import BeautifulSoup
html='''<div class="info">
    <div class="left-wrap"><span class="date">DATE-1</span></div>
</div>

<div class="clients-list">
        <div>
            <span class="client" >client1</span>
            <span class="client" >client2</span>
            <span class="client" >client3</span>
        </div>
    </div>

<div class="info">
    <div class="left-wrap"><span class="date" >DATE-2</span></div>
</div>
<div class="clients-list">
        <div>
            <span class="client" >client4</span>
            <span class="client" >client5</span>
        </div>
</div>'''

soup=BeautifulSoup(html,'html.parser')
dates=soup.find_all(class_='date')
for date in dates:
  print(date.text)
  for item in date.find_next(class_='clients-list').find_all(class_='client'):
       print(item.text)

输出

DATE-1
client1
client2
client3
DATE-2
client4
client5

Answer 2

您可以使用itertools.groupby

from bs4 import BeautifulSoup as soup
import itertools as it, re
data = soup(html, 'html.parser').find_all('span', {'class':re.compile('client|date')})
r = [[i.text for i in b] for _, b in it.groupby(data, key=lambda x:x['class'][0] == 'client')]
result = {r[i][0]:r[i+1] for i in range(0, len(r), 2)}

输出：

{'DATE-1': ['client1', 'client2', 'client3'], 'DATE-2': ['client4', 'client5']}