回到指令上去

Question

我在C++上写了一些代码，我说我是这门语言的新手。实际上，在if中给出的指令之后，我编写了一个字符串，指示用户编写一个新的输入。但是当它第二次插入变量时，程序就停止了。你知道我能做什么吗？啊，你也知道怎么在不需要按回车的情况下给用户添加字符吗？

#include <iostream>
using namespace std;

int main() {

  string line1 = "OOOOOO";
  string line2 = "OOIOOO";
  string line3 = "OOOOOO";
  string line4 = "OOOOOO";

  char I = 'I';
  char W = 'W';
  char A = 'A';
  char S = 'S';
  char D = 'D';

  char Input;

  cout << line1 << endl;
  cout << line2 << endl;
  cout << line3 << endl;
  cout << line4 << endl;

  cin >> Input;

  if (Input == D) {
    size_t found = line2.find(I);
    if (found != string::npos)
      line2[found] = 'O';
    line2[found + 1] = 'I';
    system("cls");

    cout << line1 << endl;
    cout << line2 << endl;
    cout << line3 << endl;
    cout << line4 << endl;
    cout << endl;

    cout << "x: " << found << endl;
    cin >> Input;
  }
  if (Input == A) {
    size_t found = line2.find(I);
    if (found != string::npos)
      line2[found] = 'O';
    line2[found - 1] = 'I';
    system("cls");

    cout << line1 << endl;
    cout << line2 << endl;
    cout << line3 << endl;
    cout << line4 << endl;
    cout << endl;

    cout << "x: " << found << endl;
    cin >> Input;
  }

  return 0;
}

Answer 1

试试看，我已经把你的如果改到了。

如果你在'D‘之后输入'A’，它会执行这两个循环。

#include <iostream>
using namespace std;

int main() {

  string line1 = "OOOOOO";
  string line2 = "OOIOOO";
  string line3 = "OOOOOO";
  string line4 = "OOOOOO";

  char I = 'I';
  char W = 'W';
  char A = 'A';
  char S = 'S';
  char D = 'D';

  char Input;

  cout << line1 << endl;
  cout << line2 << endl;
  cout << line3 << endl;
  cout << line4 << endl;

  cin >> Input;

  while (Input == D) {
    size_t found = line2.find(I);
    if (found != string::npos)
      line2[found] = 'O';
    line2[found + 1] = 'I';
    system("cls");

    cout << line1 << endl;
    cout << line2 << endl;
    cout << line3 << endl;
    cout << line4 << endl;
    cout << endl;

    cout << "x: " << found << endl;
    cin >> Input;
  }

while (Input == A) {
    size_t found = line2.find(I);
    if (found != string::npos)
      line2[found] = 'O';
    line2[found - 1] = 'I';
    system("cls");
    cout << line1 << endl;
    cout << line2 << endl;
    cout << line3 << endl;
    cout << line4 << endl;
    cout << endl;

    cout << "x: " << found << endl;
    cin >> Input;
  }

  return 0;
}