我在A1:C1中有标题,在A2:C5中有值(X)。范围可能不同,但我希望D列在发现范围内的/时,显示出由X分隔的标头值。
插入此vba函数是因为我有一个较旧版本的excel,而没有textjoin集成:
Function TEXTJOIN(delim As String, skipblank As Boolean, arr)
Dim d As Long
Dim c As Long
Dim arr2()
Dim t As Long, y As Long
t = -1
y = -1
If TypeName(arr) = "Range" Then
arr2 = arr.Value
Else
arr2 = arr
End If
On Error Resume Next
t = UBound(arr2, 2)
y = UBound(arr2, 1)
On Error GoTo 0
If t >= 0 And y >= 0 Then
For c = LBound(arr2, 1) To UBound(arr2, 1)
For d = LBound(arr2, 1) To UBound(arr2, 2)
If arr2(c, d) <> "" Or Not skipblank Then
TEXTJOIN = TEXTJOIN & arr2(c, d) & delim
End If
Next d
Next c
Else
For c = LBound(arr2) To UBound(arr2)
If arr2(c) <> "" Or Not skipblank Then
TEXTJOIN = TEXTJOIN & arr2(c) & delim
End If
Next c
End If
TEXTJOIN = Left(TEXTJOIN, Len(TEXTJOIN) - Len(delim))
End Function这个公式由Scott给出,以便将头放入数组中:
压下=TEXTJOIN("/",TRUE,IF(A2:C2="X",$A$1:$C$1,""))后ctrl+shift+enter
如何省略#value!错误?我试图包装一个iferror语句,但这只是在单元格中填充任何内容。

发布于 2022-02-17 10:54:12
Function TextJoin(delimiter As String, ignore_empty As Boolean, ParamArray PAitems() As Variant) As String
'like TextJoin in office 365
If ignore_empty Then
TextJoin = JoinIE(delimiter, PAitems)
Else
TextJoin = JoinKE(delimiter, PAitems)
End If
End Function
Function JoinIE(delimiter As String, ParamArray PAitems() As Variant) As String
'join ignore empty
Dim v, w
Dim s As String
Dim j As String
For Each v In PAitems
If IsArray(v) Then
For Each w In v
j = JoinIE(delimiter, w)
If Len(j) Then s = s & j & delimiter
Next
If Len(s) >= Len(delimiter) Then s = Left(s, Len(s) - Len(delimiter))
v = s
s = vbNullString
End If
If Not IsMissing(v) And Not IsError(v) Then
If Len(v) Then JoinIE = JoinIE & v & delimiter
End If
Next
If Len(JoinIE) <= Len(delimiter) Then Exit Function
JoinIE = Left(JoinIE, Len(JoinIE) - Len(delimiter))
End Function
Function JoinKE(delimiter As String, ParamArray PAitems() As Variant) As String
'join keep empty
Dim v, w
Dim s As String
For Each v In PAitems
If IsArray(v) Then
For Each w In v
s = s & JoinKE(delimiter, w) & delimiter
Next
If Len(s) >= Len(delimiter) Then s = Left(s, Len(s) - Len(delimiter))
v = s
s = vbNullString
End If
If IsMissing(v) Or IsError(v) Then v = Empty
JoinKE = JoinKE & v & delimiter
Next
If Len(JoinKE) <= Len(delimiter) Then Exit Function
JoinKE = Left(JoinKE, Len(JoinKE) - Len(delimiter))
End Functionhttps://stackoverflow.com/questions/58121842
复制相似问题