如何一天一天地递增，找到下一个期望的一天

Question

我有一个类似于['Wednesday','Sunday','Monday']的天名数组，现在我想找到下一个可用的日期，这些日期与今天日期的数组相匹配。我要约会。我试了这么久，但都没有成功。下面给出了我的代码

$datesAvailable = array();
$count = 0;

$dateToday = Carbon::now()->toDateTimeString();

//$avlDays is the array of day names
$avlDays = DB::table('doctor_schedules')
                ->select('available_days')
                ->where('department',$receivedDepartment)                                
                ->Where('doctor_id', $receivedDoctor)
                ->get();

for($k=5; $k > 0; $k++) 
{

    $dateToday = $dateToday->endOfWeek();
    // $parsedDate = Carbon::parse($dateToday);
    $dateTodayFormated = new Carbon($dateToday);
    $nextDayName = $dateTodayFormated->englishDayOfWeek;

    for($i = 0; $i <= 2; $i++)
    {
        if($avlDays === $nextDayName)
        {
            $datesAvailable[$count] = $nextDayName;
            $count++;
        }
    }
}

return (['availableDates' => $dateToday]);

解决了

Answer 1

用于当前日期使用。

now()

https://laravel.com/docs/6.x/helpers#method-now

Answer 2

碳可以做到这一点。

foreach ($avlDays as $day) {
    $nextDay = Carbon::parse("next $day");

    // do something with $nextDay...
}

Answer 3

因此，假设$avlDays返回一个碳日期范围：

$avlDays = DB::table('doctor_schedules')
    ->select('available_days')
    ->where('department',$receivedDepartment)
    ->Where('doctor_id', $receivedDoctor)
    ->get()
    ->toArray();

下面的代码假设来自['monday', 'tuesday' ...]的数组值被保存为$weekday。

如果您试图在某个工作日的范围内找到一个特定的日期，您可以这样做：

$availableAppointments = [];
foreach ($avlDays as $day) {
    if ($day->isDayOfWeek($weekday)) {
        $availableAppointments[] = $day;
    }

然后，您可以使用$availableAppointments列出一周的那一天的可用日期。