如何用python3迭代字典列表

Question

循环遍历字典结果错误列表：

AttributeError：'list‘对象没有属性'items’

改变：

for the_key, the_value in bucket.items():

至：

for the_key, the_value in bucket[0].items():

结果第一要素。我想捕捉所有的元素

bucket = [{'Name:': 'Share-1', 'Region': 'ap-south-1'}, {'Name:': 'Share-2', 'Region': 'us-west-1'}]


for the_key, the_value in bucket.items():
    print(the_key, 'corresponds to', the_value)

实际结果：

AttributeError：'list‘对象没有属性'items’

需要产出：

Name: Share-1
Region: ap-south-1

Name: Share-2
Region: us-west-1

Answer 1

因为bucket是一个列表，而不是dict，所以您应该先遍历它，对于每个dict，迭代它是items

bucket = [{'Name:': 'Share-1', 'Region': 'ap-south-1'}, {'Name:': 'Share-2', 'Region': 'us-west-1'}]

for d in bucket:
    for the_key, the_value in d.items():
        print(the_key, 'corresponds to', the_value)

输出：

Name: corresponds to Share-1
Region corresponds to ap-south-1
Name: corresponds to Share-2
Region corresponds to us-west-1

Answer 2

你可以试试这个：

for dictionary in bucket:
    for key, val in dictionary.items():
        print(the_key, 'corresponds to', the_value) 

Answer 3

您的数据有两个层，因此需要两个循环：

for dct in lst:
    for key, value in dct.items():
        print(f"{key}: {value}")
    print() # empty line between dicts