如何在查询中添加不等于的位置

Question

我试图以active is not qual to 1的形式添加一个条件，但在我的查询中我无法弄清楚它是如何正确工作的。

这里是我的查询

$career_solutions_data = DB::select("
SELECT
career_solutions.id,
role_users.role_id,
career_solutions.user_id,
career_solutions.subject,
career_solutions.date,
career_solutions.public,
career_solutions.views,
career_solutions.optional,
career_solutions.on_offer,
career_solutions.active,
users.username,
users.profile_picture,
categories.category,
categories.category_url,
categories.color,
career_solutions_categories.category as sub_category,
career_solutions_format.category as event_format,
career_solutions_certification.category as certification



FROM career_solutions



INNER JOIN categories
ON categories.id = career_solutions.topic_category_id

INNER JOIN career_solutions_format
ON career_solutions_format.id = career_solutions.topic_format_id

INNER JOIN career_solutions_certification
ON career_solutions_certification.id = career_solutions.topic_certification_id

INNER JOIN career_solutions_categories
ON career_solutions_categories.id = career_solutions.topic_subcategory_id

INNER JOIN users
ON users.id = career_solutions.user_id

LEFT JOIN role_users on role_users.role_id = users.id



INNER JOIN privacy_settings
ON privacy_settings.user_id = users.id

WHERE users.deleted_at IS NULL
AND (
(privacy_settings.career_solutions = 0 AND public = 1 )
OR (users.id IN (

SELECT contacts.contact_id
FROM contacts
WHERE contacts.user_id = $id
)
)
)

OR users.id = $id

ORDER BY date desc limit 5000
");


$role = User::with('role')
->where ('id', '=', $id)
->first();



                // $career_solutions_data;

                foreach ($career_solutions_data as $career_solution)
                {

                    preg_match('/<img.+src=[\'"](?P<src>.+?)[\'"].*>/i', $career_solution->optional, $image);
                    if(isset($image['src']))
                    {
                        $type_picture = $image['src'];
                    }
                    else{
                        $type_picture = "";
                    }

                    $temp_soluation = array();
                    $temp_soluation['type'] = 'Career Solution';
                    $temp_soluation['typee'] = 'briefcase';
                    $temp_soluation['subject'] = $career_solution->subject;

                    $temp_soluation['information'] = $career_solution->optional;
                    $temp_soluation['category'] = $career_solution->category;
                    $temp_soluation['category_url'] = $career_solution->category_url;
                    $temp_soluation['color'] = $career_solution->color;
                    $temp_soluation['all_url'] = 'search-career-solutions';
                    $temp_soluation['type_url'] = 'view-career-solutions';
                    $temp_soluation['id'] = $career_solution->id;
                    $temp_soluation['date'] = $career_solution->date;
                    $temp_soluation['public'] = $career_solution->public;
                    $temp_soluation['active'] = $career_solution->active;
                    $temp_soluation['sub_category'] = $career_solution->sub_category;
                    $temp_soluation['event_format'] = $career_solution->event_format;
                    $temp_soluation['certification'] = $career_solution->certification;
                    $temp_soluation['on_offer'] = $career_solution->on_offer;
                    $temp_soluation['username'] = $career_solution->username;
                    $temp_soluation['roleMe'] = $career_solution->optional;

                              $temp_soluation['role']  = $role->role[0]->id;


                    $temp_soluation['profile_picture'] = $career_solution->profile_picture;
                    $temp_soluation['type_picture'] = $type_picture;
                    // $news_events_opinions[] = $temp_soluation;
                    $my_career_solution[] = $temp_soluation;
                }
            }

这就是我想补充的：

WHERE `career_solutions.active` <> `1`
or
WHERE `active` <> `1`
or
WHERE `active` != `1`

但是没有working.So，我需要不显示带有active = 1.I的帖子，还有另外3个查询，不同的是，我使用了以下内容：->where("active","!=",1);，但在这里我不能使用它。

Answer 1

问题是1周围的回退:这指示MySQL搜索列名称1。

试试WHERE career_solutions.active <> 1