我试图通过将选中的值传递给SP以返回匹配的结果,但它没有返回任何内容,但问题是,当我在查询中手动给值时,它使用 in 函数在sql中工作s.Am。
这里是我的Ajax代码
<script>
$('.checked').click(function () {
var colorss =$("#colors input:checked").map(function (i, el) { return el.name; }).get();
var combinedstring = colorss.join("','");
var result = "'" +combinedstring+"'";
alert(test);
if (this.checked) {
$.ajax({
type: "POST",
url: 'FilterByColor',
data: { minimum_range: $("#minid").val(), maximum_range: $("#maxid").val(),color:result}, //--> send id of checked checkbox on other page
success: function (vlist) {
$('#card-group').empty();
for (var i in vlist) {
$('#card-group').append($('<div class="col-lg-3 col-sm-6 p-0"><div class="card product-men p-3"><div class="men-thumb-item"><img src="' + vlist[i].img1 + '" id="imgfront" class="card-img-top"><div class="men-cart-pro"><div class="inner-men-cart-pro"><a href="#" id="quickview" class="link-product-add-cart">Quick View</a>/</div></div></div><!-- card body --><div class="card-body py-3 px-2"><h5 class="card-title text-capitalize" id="mname">' + vlist[i].mname + '</h5><div class="card-text d-flex justify-content-between"><p class="text-dark font-weight-bold" id="mprize">' + vlist[i].mprize + '</p><p class="line-through" id="mdprize">' + vlist[i].mdprize + '</p></div></div><!-- card footer --><div class="card-footer d-flex justify-content-end"><h3> <a href="Purchase/AddToCarts?mid=' + vlist[i].mid + ',mrate=' + vlist[i].mrate + '" class="hub-cart phub-cart btn">Add To Cart</a></h3></div></div></div>'));
}
},
error: function () {
alert('it broke');
},
complete: function () {
alert('it completed');
}
});
}
});
</script>这是我的SP
ALTER PROCEDURE [dbo].[getWproductByColor]
@sprize int,
@eprize int,
@color char(50)
as
BEGIN
select mid,LTRIM(RTRIM(mtype))as mtype,LTRIM(RTRIM(mname))as mname,LTRIM(RTRIM(mdetails))as mdetails,LTRIM(RTRIM(mcode))as mcode,LTRIM(RTRIM(mcolor))as mcolor,msize,LTRIM(RTRIM(mctype)) as mctype,convert(date,mdate)as mdate,mdprize,mprize,mcount,mimg1,mimg2,mimg3 from [dbo].[material] where mtype='women' and (mdprize between @sprize AND @eprize)and (mcolor IN (@color)) order by mdprize asc;
END发布于 2019-09-25 07:04:42
请在Sql server中创建以下函数
CREATE FUNCTION [dbo].[SplitColor] (@InStr VARCHAR(MAX))
RETURNS @TempTab TABLE
(ColorCode Varchar(50) not null)
AS
BEGIN
;-- Ensure input ends with comma
SET @InStr = REPLACE(@InStr + ',', ',,', ',')
DECLARE @SP INT
DECLARE @VALUE VARCHAR(1000)
WHILE PATINDEX('%,%', @INSTR ) <> 0
BEGIN
SELECT @SP = PATINDEX('%,%',@INSTR)
SELECT @VALUE = LEFT(@INSTR , @SP - 1)
SELECT @INSTR = STUFF(@INSTR, 1, @SP, '')
INSERT INTO @TempTab(ColorCode) VALUES (@VALUE)
END
RETURN
END请确保传递的字符串以单个逗号结尾。
您的存储过程需要修改。
ALTER PROCEDURE [dbo].[getWproductByColor]
@sprize int,
@eprize int,
@color char(50)
as
BEGIN
select mid,LTRIM(RTRIM(mtype))as mtype,LTRIM(RTRIM(mname))as
mname,LTRIM(RTRIM(mdetails))as mdetails,LTRIM(RTRIM(mcode))as
mcode,LTRIM(RTRIM(mcolor))as mcolor,msize,LTRIM(RTRIM(mctype)) as
mctype,convert(date,mdate)as mdate,mdprize,mprize,mcount,mimg1,mimg2,mimg3
from [dbo].[material]
where mtype='women' and
(mdprize between @sprize AND @eprize) and
(mcolor IN (SELECT * FROM SplitColor(@color)))
order by mdprize asc;
END发布于 2019-09-24 14:54:03
调试得很好!
首先,在控制器函数上放置断点,其中数据来自ajax post。然后检查值是否正确传递。如果它是您想要的,那么检查您的sp调用函数以了解进一步的错误可能性(例如sp数据类型和发送数据类型)。如果这也是正确的话,
打开SSMS(Sql Server Management Studio),然后从Tools Open SQL Server Profiler跟踪在您的进程上确切执行了什么查询。
我相信你自己会发现的
https://stackoverflow.com/questions/58081182
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