我一直在使用seaborn.catplot,以便有一个条形图(下面的数据样本)将一组由一组公司分隔的counts列中的值相加:
sns.catplot(x='Bill_Name', y='counts', hue='Reason',
data=data, kind='bar', height=6, aspect=13/6,
legend=True, palette='hls')

现在,对于每个值,还有一个列year。因此,我考虑使用seaborn.FacetGrid,以便将上面的内容放在一个行的网格中。
因此,如果我正确地理解了它的工作方式,就必须将sns.FacetGrid作为row参数提供数据和year列,然后使用sns.map和sns.catplot及其相应的参数,但是这不能正常工作:
g = sns.FacetGrid(data, row="year", height=4, aspect=.5)
g = g.map(sns.catplot, x='Bill_Name', y='counts', hue='Reason',
data=data, kind='bar', height=6, aspect=13/6,
legend=True, palette='hls')我做错了什么?
下面是一个数据示例:
Bill_Name year Reason counts
0 CompanyC 2018.0 Reason6 2
1 CompanyC 2017.0 Reason5 8
2 CompanyB 2017.0 Reason3 146
3 CompanyC 2015.0 Reason6 2
4 CompanyC 2017.0 Reason1 1828
5 CompanyC 2016.0 Reason3 237
6 CompanyB 2018.0 Reason4 1097
7 CompanyC 2016.0 Reason4 11
8 CompanyB 2016.0 Reason5 12
9 CompanyC 2017.0 Reason2 834
10 CompanyB 2016.0 Reason3 97
11 CompanyC 2017.0 Reason6 714
12 CompanyA 2017.0 Reason1 4288
13 CompanyA 2016.0 Reason2 2444
14 CompanyC 2017.0 Reason3 293
15 CompanyB 2016.0 Reason1 1576
16 CompanyA 2016.0 Reason4 37
17 CompanyA 2018.0 Reason5 1
18 CompanyC 2018.0 Reason1 908
19 CompanyC 2018.0 Reason2 478
20 CompanyA 2015.0 Reason1 3826
21 CompanyB 2016.0 Reason4 119
22 CompanyB 2017.0 Reason2 1404
23 CompanyC 2016.0 Reason1 1884
24 CompanyC 2015.0 Reason4 1
25 CompanyA 2016.0 Reason1 6360
26 CompanyA 2018.0 Reason3 225
27 CompanyA 2018.0 Reason4 63
28 CompanyC 2018.0 Reason4 162
29 CompanyC 2016.0 Reason2 1504发布于 2019-10-07 12:27:55
如果将facetgrid参数添加到海运catplot中,则可以完全避免catplot。
sns.catplot(x='Bill_Name', y='counts', hue='Reason',row='year', data=data, kind='bar', height=6, aspect=13/6, legend=True, palette='hls')https://stackoverflow.com/questions/58267193
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