带有两个按钮和一个LED的高级锁存器(Arduino)

Question

我的密码怎么了？我一直在

作为赋值的左操作数所需的

值

我试图建立一个有两个按钮的SR latch，如果两个按钮被按下，发光二极管应该是低的。如果他们中的任何一个被按下，LED应该能够继续，直到它被另一个按钮重置

#include <arduinio.h>


const int buttonPin[] = {2,3};     // the number of the pushbutton pins
const int ledPin =  4;      // the number of the LED pin

// variables will change:
int buttonState1 = 0;         // variable for reading the pushbutton status
int buttonState2 = 0; 
void setup() {
  Serial.begin(9600);
  // initialize the LED pin as an output:
  pinMode(ledPin, OUTPUT);  
  digitalWrite(ledPin, LOW);  
  // initialize the pushbutton pin as an input:
  pinMode(2,INPUT);
  pinMode(3,INPUT);
}

void loop(){
 buttonState1 = digitalRead (2);
  buttonState2 = digitalRead (3);
  Serial.println(buttonState1);
  Serial.println(buttonState2);

  if (buttonState1 = 1 && buttonState2 = 0) {    
      // turn LED on:  
      digitalWrite(ledPin, HIGH);
    }
      else if (buttonState1 = 0 && buttonState2 = 1) {    
      // turn LED on:  
      digitalWrite(ledPin, HIGH);
    }
    else if (buttonState1 = 0 && buttonState2 = 0) {    
      // turn LED on:  
      digitalWrite(ledPin, HIGH);
    }
    else {    
      // turn LED on:  
      digitalWrite(ledPin, LOW);
    }
}

Answer 1

问题是在if条件下使用=而不是==。应该是这样的：

if (buttonState1 == 1 && buttonState2 == 0) {}