我有以下数据:

我希望将列“前置”和“结果”转换为字符串,删除"frozenset({ . })“格式,从而对所有行具有:
“文托林S.INAL200D 100”,而不是冻结({“文托林S.INAL200D 100”})。
我设法取得了以下结果:
prod = []
for i in df["antecedents"]:
prod.append(str(i))
new_set = {x.replace('frozenset', ''
).replace('})', ''
).replace('({', ''
).replace("'", "") for x in prod}还有更多的丙酮溶液吗?
发布于 2019-10-14 08:06:09
首先将值转换为元组或列表,然后使用DataFrame.explode
df = pd.DataFrame({
'antecedents':[frozenset({'aaa', 'bbb'})] * 3 + [frozenset({'nbb'})] * 3,
'consequents':[frozenset({'ccc'})] * 3 + [frozenset({'nbb', 'ddd'})] * 3,
'C':[1,3,5,7,1,0],
})
#print (df)
cols = ['antecedents','consequents']
df[cols] = df[cols].applymap(lambda x: tuple(x))
print (df)
antecedents consequents C
0 (bbb, aaa) (ccc,) 1
1 (bbb, aaa) (ccc,) 3
2 (bbb, aaa) (ccc,) 5
3 (nbb,) (nbb, ddd) 7
4 (nbb,) (nbb, ddd) 1
5 (nbb,) (nbb, ddd) 0df1 = (df.explode('antecedents')
.reset_index(drop=True)
.explode('consequents')
.reset_index(drop=True))
print (df1)
antecedents consequents C
0 bbb ccc 1
1 aaa ccc 1
2 bbb ccc 3
3 aaa ccc 3
4 bbb ccc 5
5 aaa ccc 5
6 nbb nbb 7
7 nbb ddd 7
8 nbb nbb 1
9 nbb ddd 1
10 nbb nbb 0
11 nbb ddd 0发布于 2022-08-12 20:44:10
首先,将两列的“前因”和“结果”转换为字符串,如下所示:
df['antecedents'] = df['antecedents'].astype('string')
df['consequents'] = df['consequents'].astype('string')然后从‘前面’和‘结果’这两个列中删除前缀"frozenset({“和后缀"})”:
df['antecedents'] = df['antecedents'].str.removeprefix("frozenset({")
df['antecedents'] = df['antecedents'].str.removesuffix("})")
df['consequents'] = df['consequents'].str.removeprefix("frozenset({")
df['consequents'] = df['consequents'].str.removesuffix("})")https://stackoverflow.com/questions/58372327
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