Regex模式只匹配一半

Question

我试图以这样一种方式来匹配下面的数据，这样我就可以在timecodes之间提取文本。

subs='''

1
00:00:00,130 --> 00:00:01,640

where you there when it 
happened?

Who else saw you?

2
00:00:01,640 --> 00:00:03,414


This might be your last chance to


come clean. Take it or leave it.
'''

Regex=re.compile(r'(\d\d:\d\d\:\d\d,\d\d\d) --> (\d\d:\d\d\:\d\d,\d\d\d)(\n.+)((\n)?).+')

我的regex匹配第一行时间码和第一行文本，但只从第二行返回几个字符，而不是整个第二行。我怎样才能让它匹配出的时间代码和实时代码之间的所有东西？

Answer 1

当前方法的一个可能问题是，在试图捕获时间戳之间的所有内容时，您没有使用DOT模式。我有re.search在DOT的所有模式工作：

subs="""

1 00:00:00,130 --> 00:00:01,640

where you there when it happened?

Who else saw you?

2 00:00:01,640 --> 00:00:03,414

This might be your last chance to

come clean. Take it or leave it. """
match = re.search(r'\d+ \d{2}:\d{2}:\d{2},\d+ --> \d{2}:\d{2}:\d{2},\d+\s*(.*)\d+ \d{2}:\d{2}:\d{2},\d+ --> \d{2}:\d{2}:\d{2},\d+', subs, flags=re.DOTALL)
if match:
    print match.group(1)
else:
    print 'NO MATCH'

这些指纹：

where you there when it happened?

Who else saw you?

Answer 2

我不确定，但我认为下面的解决方案更适用于你的情况.

使用下面的解决方案，您不仅可以在时间代码之间提取文本，而且还可以将文本连接到时间代码。

import re

multiline_text=\
"""

1 00:00:00,130 --> 00:00:01,640

where you there when it happened?

Who else saw you?

2 00:00:01,640 --> 00:00:03,414

This might be your last chance to

come clean. Take it or leave it.
"""

lines = multiline_text.split('\n')
dict = {}
current_key = None;

for line in lines:
  is_key_match_obj = re.search('([\d\:\,]{12})(\s-->\s)([\d\:\,]{12})', line)
  if is_key_match_obj:
    current_key = is_key_match_obj.group()
    continue

  if current_key:
    if current_key in dict:
      if not line:
        dict[current_key] += '\n'
      else:
        dict[current_key] += line
    else:
      dict[current_key] = line

print(dict)

Answer 3

您也可以不使用DOTALL获得匹配。

匹配第1组中的timecode和capture，匹配所有不以timecode开头的行，这些行使用的是负前瞻性。

^\d{2}:\d{2}:\d{2},\d+ --> \d{2}:\d{2}:\d{2},\d+((?:\r?\n(?!\d{2}:\d{2}:\d{2},\d+ --> \d{2}:\d{2}:\d{2},\d).*)*)

各部分

• 字符串的^开始
• \d{2}:\d{2}:\d{2},\d+ --> \d{2}:\d{2}:\d{2},\d+匹配时间码模式
• ( Capture group 1
  • (?:非捕获群
    • \r?\n匹配新的留置权
    • (?!\d{2}:\d{2}:\d{2},\d+ --> \d{2}:\d{2}:\d{2},\d)负向前看，不要断言时间码
    • .*匹配除换行符0+时间以外的任何字符

​

- `)*` Close noncapturing group and repeat 0+ times

​

• )封闭捕获组1

Regex演示