如何在经过X时间后使Ruby超时成为HTTP请求

Question

我正在尝试检测Vagrant主机是否在本地连接到我需要访问的网络。如果不是，我想要求并配置一个代理，这样我就可以下载构建项目所需的一些内部资源。

无论成功或失败，如何在给定的秒数之后发出超时的HTTP请求？

我期望以下代码在经过的时间内返回1或2秒：

HTTP_NETWORK_TEST_HOST = '172.16.0.1'

start1 = Time.now
begin
    http = Net::HTTP.new(HTTP_NETWORK_TEST_HOST, '80')
    http.read_timeout = 2
    http.open_timeout = 2
    response = http.start do |http|
        http.get('/')
    end
    NETWORK_PROXY_NEEDED = false
rescue Timeout::Error => e
    NETWORK_PROXY_NEEDED = true
end
finish1 = Time.now

start2 = Time.now
begin
    Timeout::timeout(1) {
        http = Net::HTTP.new(HTTP_NETWORK_TEST_HOST, '80')
        response = http.start do |http|
            http.get('/')
        end
    }
    NETWORK_PROXY_NEEDED = false
rescue
    NETWORK_PROXY_NEEDED = true
end
finish2 = Time.now


start3 = Time.now
begin
    http = Net::HTTP.start(HTTP_NETWORK_TEST_HOST, '80', {read_timeout: 5, open_timeout: 5})
    response =  http.get('/')
    NETWORK_PROXY_NEEDED = false
rescue Timeout::Error => e
    NETWORK_PROXY_NEEDED = true
end
finish3 = Time.now


puts 'time 1'
puts finish1 - start1

puts 'time 2'
puts finish2 - start2

puts 'time 3'
puts finish3 - start3

在以下方面的成果：

time 1
21.003133
time 2
21.012332
time 3
21.009758

的答案是由freenode： #ruby上的al2o3-cr提供给我的。

https://gist.github.com/gr33n7007h/d041f4fbc08f0e065854bb180330c3ac

NETWORK_PROXY_NEEDED = 
begin
  Socket.tcp(TEST_HOST, 80, connect_timeout: 1)&.close
  false
rescue Errno::ETIMEDOUT
  true
end

Answer 1

的答案是由freenode： #ruby上的al2o3-cr提供给我的。

https://gist.github.com/gr33n7007h/d041f4fbc08f0e065854bb180330c3ac

NETWORK_PROXY_NEEDED = 
begin
  Socket.tcp(TEST_HOST, 80, connect_timeout: 1)&.close
  false
rescue Errno::ETIMEDOUT
  true
end