如何在一个函数中使用另一个函数中的值

Question

我试图在addVat函数中使用sales函数中的用户输入。

Sales_Figures = []

def sales():
    num = int((input("Please enter sales figures: ")))
    Sales_Figures = [num]
    while num != -1:
        num = int(input("Please enter sales figures: "))
        Sales_Figures.append(num)

    print("The sales figures entered were:", end=" ")
    for num in Sales_Figures:
        if num != -1:
            print(num, end=", ")

    print("The sales figures including VAT are")
    return Sales_Figures

def addVat():

sales()

Answer 1

给定代码段的问题是您重写了Sales_Figures。您可以删除第二行：

Sales_Figures = [num]

也就是说，按照以下方式定义您的方法(在这个解决方案中，您不需要返回列表，因为它是在外部定义的)：

def sales():
    num = 0
    while num != -1:
        num = int(input("Please enter sales figures: "))
        Sales_Figures.append(num)

    print("The sales figures entered were:", end=" ")
    for num in Sales_Figures:
        if num != -1:
            print(num, end=", ")

    print("The sales figures including VAT are")

或者，您可以在方法中定义Sales_Figures并返回它：

def sales():
    num = 0
    Sales_Figures = []
    while num != -1:
        num = int(input("Please enter sales figures: "))
        Sales_Figures.append(num)

    print("The sales figures entered were:", end=" ")
    for num in Sales_Figures:
        if num != -1:
            print(num, end=", ")

    print("The sales figures including VAT are")
    return Sales_Figures

现在调用该方法时，请使用返回值

Sales_Figures = sales()

最后，VAT_RATE = 1.05 def addVat(s)：为x返回VAT_RATE*x

addVat(Sales_Figures)

Answer 2

您可以简单地将sales()函数的返回参数放入变量中，然后将其传递给addVat()。

Sales_Figures = []

def sales():
    while num != -1:
        num = int(input("Please enter sales figures: "))
        Sales_Figures.append(num)

    print("The sales figures entered were:", end=" ")
    for num in Sales_Figures:
        if num != -1:
            print(num, end=", ")

    print("The sales figures including VAT are")
    return Sales_Figures
saleFigures= sales()
def addVat(saleFigures):