转换父/子结构js中的嵌套对象

Question

我尝试转换这个结构(每个子对象都是属性)：

​

const tree = {
  "Parent 1" : {
    "Children1": {
      "Children2": {
          "#1": { info: {}},
          "#2": { info: {}}.
          "#3": { info: {}}
    },
    "Children1-1": {
      "Children2-2": {
          "#1": { info: {}},
          "#2": { info: {}}.
          "#3": { info: {}}
    }
  },
  "Parent 2": {
  ...
   }
};

​

在这个具有父子视图的树结构中。但在我的树的尽头我不需要孩子

​

const resultTeee = [
  {
    name: 'Parent 1',
    children: [
      {
        name: 'Children 1',
        children: [
          {
            name: 'Children 2',
            children: [
              {name: "#1", info: {}},
              {name: "#2", info: {}}
            ]
          }
        ]
      },
      {
        name: 'Children 1-1',
        children: [
          {
            name: 'Children 2-2',
            children: [
              {name: "#1", info: {}},
              {name: "#2", info: {}}
            ]
          }
        ]
      }
    ]
  },
  {
    name: 'Parent 2'
    ....
  }
]

​

我尝试了“遍历树”方法，但不知道如何切换新的子路径。对象可以在每个级别上具有多个嵌套结构。

Answer 1

const toArrayTree = (obj) => {
    return Object.keys(obj).map(key => {
        return {name: key, children: [toArrayTree(obj[key])]}
    })
}

用于测试的对象

const tree = {
    "Parent 1" : {
        "Children1": {
            "Children2": {
                "#1": { info: {}},
                "#2": { info: {}},
                "#3": { info: {}},
            }
        },
    },
    "Parent 2" : {
        "Children2.1": {
            "Children2.2": {
                "#4": { info: {}},
                "#5": { info: {}},
                "#6": { info: {}},
            }
        },
    },
};

但是就像阿迪加说的，为什么最后一棵树不是{ name: 'info', children: [] }

更新解决方案

const toArrayTree = (obj) => {
    return Object.keys(obj).map(key => {
        return typeof obj[key] === 'object' ?
            {name: key, children: [toArrayTree(obj[key])]} :
            {name: key, [key]: obj[key]};
    })
}

使用Object(v) === v确实是个坏主意，因为如果v是函数，例如