我正在使用SQLite数据库开发一个登录系统。我已经有了一个注册表单,它可以很好地创建所有用户,我还创建了一个方法来检查输入到EditText中的用户名是否存在。但是现在我的问题是,你将如何从那个用户检索所有相关信息,例如,我还需要检查那个特定用户的密码是否匹配,我还需要从数据库中的用户那里检索一些测试分数,然后在主页中显示它们。下面是用于登录用户的主要活动中的代码:
public void loginUser() {
EditText usernameInput = findViewById(R.id.login_username);
EditText passwordInput = findViewById(R.id.login_password);
String loginUsername = usernameInput.getText().toString();
String loginPassword = passwordInput.getText().toString();
if(loginUsername.matches("") || loginPassword.matches("")) {
Toast.makeText(this, "Fields cannot be empty", Toast.LENGTH_SHORT).show();
} else {
if (dbHelper.ifUserExists(loginUsername)) {
//password verification and login
//how to retrieve relevant users password and compare to password input?
} else {
Toast.makeText(this, "Incorrect username or password", Toast.LENGTH_SHORT).show();
}
}
}下面是来自databaseHelper的检查用户是否存在的方法:
public boolean ifUserExists(String user) {
SQLiteDatabase db = this.getReadableDatabase();
Cursor cursor = db.query(TABLE_USERS,
new String[]{KEY_ID, KEY_USERNAME, KEY_PASSWORD, KEY_SAT_READING, KEY_SAT_MATH, KEY_ACT_READING, KEY_ACT_MATH},
KEY_USERNAME + "=?",
new String[]{user},
null, null, null);
if(cursor != null && cursor.moveToFirst()&& cursor.getCount() > 0) {
return true;
} else {
return false;
}
}发布于 2019-11-23 02:19:21
您可以使用的方法之一是拥有一个包含保存数据的变量的用户对象。使用进程而不是返回布尔值时,这个inconjuction返回用户或null。
也许可以根据您的代码来考虑这个演示应用程序,为了简洁起见,它在数据库帮助程序中包含了一个用户类。
DatabaseHelper.java :-
public class DatabaseHelper extends SQLiteOpenHelper {
public static final String DBNAME = "mydb";
public static final int DBVERSION = 1;
public static final String TABLE_USERS = "users";
public static final String KEY_ID = BaseColumns._ID;
public static final String KEY_USERNAME = "username";
public static final String KEY_PASSWORD = "password";
public static final String KEY_SAT_READING = "reading";
public static final String KEY_SAT_MATH = "satmath";
public static final String KEY_ACT_READING = "actreading";
public static final String KEY_ACT_MATH = "actmath";
SQLiteDatabase db;
public DatabaseHelper(Context context) {
super(context, DBNAME, null, DBVERSION);
db = this.getWritableDatabase();
}
@Override
public void onCreate(SQLiteDatabase db) {
String users_crt_sql = "CREATE TABLE IF NOT EXISTS " + TABLE_USERS +
"(" +
KEY_ID + " INTEGER PRIMARY KEY," +
KEY_USERNAME + " TEXT UNIQUE," +
KEY_PASSWORD + " TEXT," +
KEY_SAT_READING + " TEXT," +
KEY_SAT_MATH + " TEXT," +
KEY_ACT_READING + " TEXT," +
KEY_ACT_MATH + " TEXT" +
")";
db.execSQL(users_crt_sql);
}
@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
}
public long insertNewUser(String name, String password) {
ContentValues cv = new ContentValues();
cv.put(KEY_USERNAME,name);
cv.put(KEY_PASSWORD,password);
return db.insert(TABLE_USERS,null,cv);
}
public User checkUser(String name, String password) {
User rv = null;
Cursor csr = db.query(
TABLE_USERS,
null,
KEY_USERNAME + "=? AND " + KEY_PASSWORD + "=?",
new String[]{name,password},
null,null,null
);
if (csr.moveToFirst()) {
rv = new User();
rv.setUserId(csr.getLong(csr.getColumnIndex(KEY_ID)));
rv.setUserName(name);
rv.setUserPassword("");
rv.setUserSatReading(csr.getString(csr.getColumnIndex(KEY_SAT_READING)));
rv.setUserSatMath(csr.getString(csr.getColumnIndex(KEY_SAT_MATH)));
rv.setUserActReading(csr.getString(csr.getColumnIndex(KEY_ACT_READING)));
rv.setUserActMath(csr.getString(csr.getColumnIndex(KEY_ACT_MATH)));
}
csr.close();
return rv;
}
public class User {
long userId;
String userName;
String userPassword;
String userSatReading;
String userSatMath;
String userActReading;
String userActMath;
public User() {
}
public User(String name, String password) {
this(-1L, name, password, null, null, null, null);
}
public User(long id, String name, String password, String satReading, String satMath, String actReading, String actmath) {
this.userId = id;
this.userName = name;
this.userPassword = password;
this.userSatReading = satReading;
this.userSatMath = satMath;
this.userActReading = actReading;
this.userActMath = actmath;
}
public long getUserId() {
return userId;
}
public void setUserId(long userId) {
this.userId = userId;
}
public String getUserName() {
return userName;
}
public void setUserName(String userName) {
this.userName = userName;
}
public String getUserPassword() {
return userPassword;
}
public void setUserPassword(String userPassword) {
this.userPassword = userPassword;
}
public String getUserSatReading() {
return userSatReading;
}
public void setUserSatReading(String userSatReading) {
this.userSatReading = userSatReading;
}
public String getUserSatMath() {
return userSatMath;
}
public void setUserSatMath(String userSatMath) {
this.userSatMath = userSatMath;
}
public String getUserActReading() {
return userActReading;
}
public void setUserActReading(String userActReading) {
this.userActReading = userActReading;
}
public String getUserActMath() {
return userActMath;
}
public void setUserActMath(String userActMath) {
this.userActMath = userActMath;
}
}
}。
在下面的活动中使用上述内容,这反映了您现有的代码和您想要实现的目标。
在最初启动时,应用程序添加了一个用户(用于妖魔化),该用户的名字是Admin,密码是UI由一个显示未登录的textView !(显示顶部)、两个编辑文本(按照您的代码)和一个登录按钮组成。
MainActivity.java
public class MainActivity extends AppCompatActivity {
DatabaseHelper dbHelper;
DatabaseHelper.User current_user = null;
EditText loginUsername, loginPassword;
TextView status;
Button login;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
status = this.findViewById(R.id.status);
loginUsername = this.findViewById(R.id.login_username);
loginPassword = this.findViewById(R.id.login_password);
login = this.findViewById(R.id.login);
login.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
loginUser();
}
});
dbHelper = new DatabaseHelper(this);
dbHelper.insertNewUser("Admin","adminpassword");
}
private void loginUser() {
if (
loginUsername.getText().toString() == null
|| loginUsername.getText().toString().length() < 1
||loginPassword.getText().toString() == null
|| loginPassword.getText().toString().length() < 1) {
Toast.makeText(this, "Fields cannot be empty", Toast.LENGTH_SHORT).show();
return;
}
if ((current_user = dbHelper.checkUser(loginUsername.getText().toString(),loginPassword.getText().toString())) != null) {
loginUsername.setVisibility(View.GONE);
loginPassword.setVisibility(View.GONE);
login.setText("DO SOMETHNG");
login.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
Toast.makeText(v.getContext(),"Hello " +
current_user.getUserName() +
" you are logged in so you can do something!",Toast.LENGTH_SHORT).show();
}
});
status.setText("Successfully Logged-In as " + current_user.getUserName());
} else {
Toast.makeText(this, "Incorrect username or password", Toast.LENGTH_SHORT).show();
}
}
}结果
初始运行

e 139不正确的用户名或密码消息进行烤烤。<代码142输入有效的用户名和密码:- F 143<>H144在E 145的topd处被完全记录为E 145记录在哪里?<?<?是用于用户名和密码被删除的username).
The编辑文本。,Login按钮更改为,根据:-做某事

https://stackoverflow.com/questions/59002935
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