我有以下两门课
条目
public class Entry
{
public Guid Id { get; set; }
public IEnumerable<Data> Data { get; set; }
}EntryData
public class EntryData
{
public string Type { get; set; }
public object Data { get; set; }
}我有一组不同的应用程序,它们向队列生成消息,然后在单独的应用程序中使用该队列,以便将数据存储在elasticsearch中。
我对所有消息使用一个CorrelationId,我希望在elasticsearch中使用这个ID作为ID。因此,鉴于以下数据:
var id = Guid.Parse("1befd5b62b944b4aa600c85632159e11");
var entries = new List<Entry>
{
new Entry
{
Id = id,
Data = new List<EntryData>
{
new EntryData
{
Data = DateTime.UtcNow,
Type = "APPLICATION1_Received"
},
new EntryData
{
Data = DateTime.UtcNow,
Type = "APPLICATION1_Validated"
},
new EntryData
{
Data = DateTime.UtcNow,
Type = "APPLICATION1_Published"
},
}
},
new Entry
{
Id = id,
Data = new List<EntryData>
{
new EntryData
{
Data = DateTime.UtcNow,
Type = "APPLICATION2_Received"
},
new EntryData
{
Data = DateTime.UtcNow,
Type = "APPLICATION2_Validated"
},
new EntryData
{
Data = DateTime.UtcNow,
Type = "APPLICATION2_Published"
},
}
},
new Entry
{
Id = id,
Data = new List<EntryData>
{
new EntryData
{
Data = DateTime.UtcNow,
Type = "APPLICATION3_Received"
},
new EntryData
{
Data = DateTime.UtcNow,
Type = "APPLICATION3_Validated"
},
new EntryData
{
Data = DateTime.UtcNow,
Type = "APPLICATION3_Published"
},
}
},
};我希望将其保存为elasticsearch中的one entry,其中ID == 1befd5b6-2b94-4b4a-a600-c85632159e11和包含9元素的data数组。
当我试着做以下几件事时,我有点为让它起作用而挣扎:
var result = await _elasticClient.BulkAsync(x => x.Index("journal").UpdateMany(entries, (descriptor, entry) => {
descriptor.Doc(entry);
return descriptor.Upsert(entry);
}), cancellationToken);但是这只是覆盖数据数组中已经存在的内容,计数是3而不是9(只保存了Application3条目)。
那么,能不能做我想做的事呢?我以前从未和elasticsearch合作过,所以感觉好像我错过了一些简单的东西。:)
发布于 2019-12-07 14:24:46
设法像这样解决这个问题:
var result = await _elasticClient.BulkAsync(x => x.Index("journal").UpdateMany(entries, (descriptor, entry) => {
var script = new InlineScript("ctx._source.data.addAll(params.data)")
{
Params = new Dictionary<string, object> {{"data", entry.Data}}
};
descriptor.Script(b => script);
return descriptor.Upsert(entry);
}), cancellationToken);https://stackoverflow.com/questions/59226587
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