如何将较长的列名列表替换为数据集中的小名？

Question

• --我有一个列名的列表，它们太长了，以致于代码混乱。我想用一个更短的列表替换列名列表。

，

• ，这里是列的示例：

    non_multi_choice = ["what_is_the_highest_level_of_formal_education_that_you_have_attained_or_plan_to_attain_within_the_next_2_years",
          "select_the_title_most_similar_to_your_current_role_or_most_recent_title_if_retired_selected_choice",
          "in_what_industry_is_your_current_employer_contract_or_your_most_recent_employer_if_retired_selected_choice",
          "how_many_years_of_experience_do_you_have_in_your_current_role",
          "what_is_your_current_yearly_compensation_approximate_usd",
          "does_your_current_employer_incorporate_machine_learning_methods_into_their_business",
          "of_the_choices_that_you_selected_in_the_previous_question_which_ml_library_have_you_used_the_most_selected_choice",
          "approximately_what_percent_of_your_time_at_work_or_school_is_spent_actively_coding"]

    shorter_names = ["highest_level_of_formal_education",
      "job_title",
      "current_industry",
      "years_of_experience",
      "yearly_compensation",
      "does_your_current_employer_incorporate_machine_learning_methods_into_their_business",
      "which_ml_library_have_you_used_the_most_selected_choice",
      "what_percent_of_your_time_at_work_is_spent_actively_coding"]

• 我想将第一个列表中的每个名称替换为第二个列表中相应的名称。

Answer 1

像这样的事怎么样：

for index, item in enumerate(non_multi_choice):
  non_multi_choice[index] = shorter_names[index]

Answer 2

如果这些列包含所有列名，则：

df.columns = shorter_names

如果不是

df.rename(columns = {old:new for old, new in zip(non_multi_choice, shorter_names})