如何合并两个字典，其中值是具有相同键的字符串

Question

我有两本字典。

gen1 = {0: 'RR', 1: 'RR', 2: 'rR', 3: 'rR', 4: 'RR', 5: 'RR', 6: 'rR', 7: 'rR',
      8: 'Rr', 9: 'Rr', 10: 'rr', 11: 'rr', 12: 'Rr', 13: 'Rr', 14: 'rr', 15: 'rr'}

和

gen2 = {0: 'PP', 1: 'PP', 2: 'PP', 3: 'PP', 4: 'PP', 5: 'PP', 6: 'PP', 7: 'PP',
      8: 'PP', 9: 'PP', 10: 'PP', 11: 'PP', 12: 'PP', 13: 'PP', 14: 'PP', 15: 'PP'}

我想用同样的键连接他们

gen3 = {0: 'RRPP', 1: 'RRPP', 2: 'rRPP', 3: 'rRPP', 4: 'RRPP', 5: 'RRPP', 6: 'rRPP', 7: 'rRPP',
        8: 'RrPP', 9: 'RrPP', 10: 'rrPP', 11: 'rrPP', 12: 'RrPP', 13: 'RrPP', 14: 'rrPP', 15: 'rrPP'}

Answer 1

您可以使用字典理解和f-strings构建一个新的字典：

{k:f'{v}{gen2.get(k, "")}' for k,v in gen1.items()}
# {k:'{}{}'.format(v, gen2.get(k, "")) for k,v in gen1.items()} # python versions under 3.6

{0: 'RRPP', 1: 'RRPP', 2: 'rRPP', 3: 'rRPP', 4: 'RRPP', 5: 'RRPP', 6: 'rRPP', 
 7: 'rRPP', 8: 'RrPP', 9: 'RrPP', 10: 'rrPP', 11: 'rrPP', 12: 'RrPP', 13: 'RrPP', 
 14: 'rrPP', 15: 'rrPP'}

Answer 2

一分为二的理解力--与@yatu的回答略有不同。这将对来自gen1和gen2的所有唯一键进行操作--如果一个键只存在于其中一个字典中，则生成的字典将只具有相应的gen字典中的值。

>>> gen1 = {0: 'RR', 1: 'RR', 2: 'rR', 3: 'rR', 4: 'RR', 5: 'RR', 6: 'rR', 7: 'rR', 8: 'Rr', 9: 'Rr', 10: 'rr', 11: 'rr', 12: 'Rr', 13: 'Rr', 14: 'rr', 15: 'rr'}
>>> gen2 = {0: 'PP', 1: 'PP', 2: 'PP', 3: 'PP', 4: 'PP', 5: 'PP', 6: 'PP', 7: 'PP', 8: 'PP', 9: 'PP', 10: 'PP', 11: 'PP', 12: 'PP', 13: 'PP', 14: 'PP', 15: 'PP'}
>>> {k: gen1.get(k, '') + gen2.get(k, '') for k in set(list(gen1.keys()) + list(gen2.keys()))}
{0: 'RRPP',
 1: 'RRPP',
 2: 'rRPP',
 3: 'rRPP',
 4: 'RRPP',
 5: 'RRPP',
 6: 'rRPP',
 7: 'rRPP',
 8: 'RrPP',
 9: 'RrPP',
 10: 'rrPP',
 11: 'rrPP',
 12: 'RrPP',
 13: 'RrPP',
 14: 'rrPP',
 15: 'rrPP'}

Answer 3

如果您确信gen1和gen2具有完全相同的键，则应该可以这样做：

gen3 = { k: gen1[k] + gen2[k] for k in gen1 }