如何创建带有菜单的Python、二进制、八进制和HexaDecimal转换器？

Question

我对这件事很陌生，请容忍我。我正在设计一个带有菜单的转换器，该菜单允许用户选择使用哪种数据类型(从数据类型到数据类型)来转换(例如)二进制到十进制(反之亦然)。任何帮助都将不胜感激。

到目前为止，当我运行程序时，代码会执行并显示菜单，询问我想要转换的内容，但这是我目前所能掌握的。

这是我迄今所做的代码..。

    # introductory menu
    print ("What are you converting from?");

def menu ():
    print ("\n1. Decimal")
    print ("2. Binary")
    print ("3. Octal")
    print ("4. Hexadecimal")
    print ("5. Exit")
    pick = int(input("Please enter an option: "))
    return pick

def toBinary (b):
    return bin(b)

def toDecimal (d):
    return int(d)

def toOctal (o):
    return oct(o)

def toHexadecimal (h):
    return hex(h)


def main():
    choice=menu()
    while choice !=5:
        if choice == 1:
            #convert Decimal to ?
            d = eval(input("What is your Decimal Value?: "))
            print(int(toDecimal (d)))

        elif choice == 2:
            #convert Binary to ?
            b = eval(input("What is your Binary Value?: "))
            print(str(toBinary (b)))

        elif choice == 3:
            #convert Octal to ?
            o = eval(input("What is your Octal Value?: "))
            print(str(toOctal (o)))

        elif choice == 4:
            #convert Hexadecimal to ?
            h = eval(input("What is your Hexadecimal Value?: "))
            print(str(toHexadecimal (h)))

        else:
            print ("Whoops!!! That is an Invalid Entry")

main()

以下是正在运行的节目的截图。

正如你所看到的，它并没有做我真正想做的事情。

节目运行截图

Answer 1

您需要将menu()方法包含在while循环中，否则选择值将始终是相同的，并且永远不会从2中更改(就像您共享的屏幕截图一样)。

  choice=0
  while choice !=5:
        choice=menu()

此外，如果希望转换程序正常工作，则需要添加另一个方法来选择要转换输入值的方式：

def transform_to(value):
    print("Transform to ")
    choice = menu()
    if choice == 1:
        print(int(toDecimal (value)))
        choice=5

    elif choice == 2:
        print(str(toBinary (value)))
        choice=5


    elif choice == 3:
        print(str(toOctal (value)))
        choice=5

    elif choice == 4:
        print(str(toHexadecimal (value)))
        choice=5

所以你的最后剧本是：

# introductory menu
print ("What are you converting from?");

def menu ():
    print ("\n1. Decimal")
    print ("2. Binary")
    print ("3. Octal")
    print ("4. Hexadecimal")
    print ("5. Exit")
    pick = int(input("Please enter an option: "))
    return pick

def toBinary (b):
    return bin(b)

def toDecimal (d):
    return int(d)

def toOctal (o):
    return oct(o)

def toHexadecimal (h):
    return hex(h)


def transform_to(value):
    print("Transform to ")
    choice = menu()
    if choice == 1:
        print(int(toDecimal (value)))
        choice=5

    elif choice == 2:
        print(str(toBinary (value)))
        choice=5


    elif choice == 3:
        print(str(toOctal (value)))
        choice=5

    elif choice == 4:
        print(str(toHexadecimal (value)))
        choice=5

def main():
    choice=0
    while choice !=5:
        choice=menu()
        if choice == 1:
            #convert Decimal to ?
            d = eval(input("What is your Decimal Value?: "))
            transform_to(d)
            print(int(toDecimal (d)))

        elif choice == 2:
            #convert Binary to ?
            b = eval(input("What is your Binary Value?: "))
            transform_to(b)


        elif choice == 3:
            #convert Octal to ?
            o = eval(input("What is your Octal Value?: "))
            transform_to(o)


        elif choice == 4:
            #convert Hexadecimal to ?
            h = eval(input("What is your Hexadecimal Value?: "))
            transform_to(h)

main()