为什么我不能在蟒蛇中将DNA转换成mRNA？

Question

代码：

n = 3

DNA-Sequence = { #dictionary of DNA
    "Phenylalanine": ["UUU", "UUC"],
    "Leucine": ["UUA", "CUU", "CUC", "CUA", "CUG", "UUG"],
    "Isoleucine": ["AUU", "AUC", "AUA"],
    "Methionine": "AUG",
    "Valine": ["GUU", "GUC", "GUA", "GUG"],
    "Serine": ["UCU", "UCC", "UCA", "UCG"],
    "Proline": ["CCU", "CCC", "CCA", "CCG"],
    "Threonine": ["ACU", "ACC", "ACA", "ACG"],
    "Alanine": ["GCU", "GCC", "GCA", "GCG"],
    "Tyrosine": ["UAU", "UAC"],
    "Histidine": ["CAU", "CAC"],
    "Glutamine": ["CAA", "CAG"],
    "Asparagine": ["AAU", "AAC"],
    "Lysine": ["AAA", "AAG"],
    "Asparatic Acid": ["GAU", "GAC"],
    "Glutamic Acid": ["GAA", "GAG"],
    "Cysteine": ["UGU", "UGC"],
    "Trytophan": "UGG",
    "Arginine": ["CGU", "CGC", "CGA", "CGG", "AGG", "AGA"],
    "Serine": ["AGU", "AGC"],
    "Glycine": ["GGU", "GGC", "GGA", "GGG"]
}

lookup_dict = {k: key for key, values in DNA-Sequence.items() for k in values} #this is used to find the values in the dictionary using the inputDNA
inputDNA = input("Enter your DNA sequence: ")
inputDNA = inputDNA.upper()
print("Your DNA sequence is", inputDNA)
str(inputDNA)
RNA = inputDNA.replace('C', 'G') #this is me trying to convert DNA sequence to RNA
RNA = RNA.replace('A', "U") #this is me trying to convert DNA sequence to RNA
RNA = RNA.replace('T', 'A') #this is me trying to convert DNA sequence to RNA
print(RNA)

b = len(inputDNA)

if b % 3 == 0: #if the length of inputDNA is a multiple of 3
  for k in (inputDNA[i:i + n] for i in range(0, len(inputDNA), n)):
    for _, values in DNA-Sequence.items():
      if k in values:
        print(lookup_dict[k], end=" ")
        break
    else: #if the length of inputDNA is not a multiple of 3
      print("I hate u")

发生了什么：

Enter your DNA sequence: CCATAGCACGTT
Your DNA sequence is: CCATAGCACGTT
GGUAUGGUGGAA
Proline I hate u
Histidine I hate u

我想要的是：

Enter your DNA sequence: CCATAGCACGTT
Your DNA sequence is: CCATAGCACGTT #this is because I need to convert DNA sequence to RNA but I am not sure of the formula and how to do it in python
GGUAUCGUGCAA
Your amino acids chain is: Glycine, Isoleucine, Valine, Glutamine

为什么我要获得A的输出，以及如何将它修复成我想要的输出？我知道我不是在做RNA = RNA.replace('G', 'C')，但是当我这样做时，输出就变成了

Enter your DNA sequence: CAACAUGCU
Your DNA sequence is CAACAUGCU
A
Glutamine Histidine Alanine 

或者一些类似的东西，但绝对不是，我不知道发生了什么。请帮帮忙？

Answer 1

据我所见，您可以对遇到问题的替换进行以下操作；可以通过1次转换调用或2次依赖于您的首选项来完成：

a = input("Enter your DNA sequence: ")
a = a.upper()
print("Your DNA sequence is", a)
# RNA = a.translate(str.maketrans({'G': 'C', 'C': 'G'}))
# RNA = RNA.translate(str.maketrans({'A': 'U', 'T': 'A'}))
RNA = a.translate(str.maketrans({'G': 'C', 'C': 'G', 'A': 'U', 'T': 'A'}))
print(RNA)

产出如下：

Enter your DNA sequence: CCATAGCACGTT
Your DNA sequence is CCATAGCACGTT
GGUAUCGUGCAA

关于氨基酸的印刷：

b = len(RNA)

if b % 3 == 0: #if the length of inputDNA is a multiple of 3
  for k in (RNA[i:i + n] for i in range(0, len(RNA), n)):
    for kk, val in DNA_Sequence.items():
      if k in val:
        print(kk, end=" ")
        break
else: #if the length of inputDNA is not a multiple of 3
    print("I hate u")

通知

该表不是DNA表，而是RNA (您有U)，因此需要在循环中使用RNA，输出如下：

甘氨酸异亮氨酸谷氨酰胺

Answer 2

我为另一个人写了一个熊猫解决方案：

import pandas as pd
df =  pd.DataFrame(list(xdict.items()))

import re
def lookupKeys(df, key):
  name = []
  matches = re.findall(r'...', key)
  for match in matches:
      name.append(df[df[1].apply(lambda x: True if key in x else x) == True][0].reset_index()[0][0])
  return name


lookupKeys(df, 'GGUAUCGUGCAA')                                                                                                                                                      
# ['Glycine', 'Isoleucine', 'Valine', 'Glutamine']

Answer 3

好的，有一些语法错误，但是让它启动并运行.

n = 3

xdict = {
    "Phenylalanine": ["UUU", "UUC"],
    "Leucine": ["UUA", "CUU", "CUC", "CUA", "CUG", "UUG"],
    "Isoleucine": ["AUU", "AUC", "AUA"],
    # Put the 'AUG' on brackets []
    "Methionine": ["AUG"],
    "Valine": ["GUU", "GUC", "GUA", "GUG"],
    "Serine": ["UCU", "UCC", "UCA", "UCG"],
    "Proline": ["CCU", "CCC", "CCA", "CCG"],
    "Threonine": ["ACU", "ACC", "ACA", "ACG"],
    "Alanine": ["GCU", "GCC", "GCA", "GCG"],
    "Tyrosine": ["UAU", "UAC"],
    "Histidine": ["CAU", "CAC"],
    "Glutamine": ["CAA", "CAG"],
    "Asparagine": ["AAU", "AAC"],
    "Lysine": ["AAA", "AAG"],
    "Asparatic Acid": ["GAU", "GAC"],
    "Glutamic Acid": ["GAA", "GAG"],
    "Cysteine": ["UGU", "UGC"],
    "Trytophan": "UGG",
    "Arginine": ["CGU", "CGC", "CGA", "CGG", "AGG", "AGA"],
    "Serine": ["AGU", "AGC"],
    "Glycine": ["GGU", "GGC", "GGA", "GGG"]
}

lookup_dict = {k: key for key, values in xdict.items() for k in values}
a = input("Enter your DNA sequence: ")
a = a.upper()
print("Your DNA sequence is", a)
str(a)
RNA = a.replace('C', 'G')
RNA = RNA.replace('A', "U")
RNA = RNA.replace('T', 'A')
print(RNA)

b = len(a)

# Introduced a new flag variable
val = ''

if b % 3 == 0:
    # a replaced with RNA
  for k in (RNA[i:i + n] for i in range(0, len(a), n)):
      val += lookup_dict[k] + ' '

elif b % 3 != 0:
  print("Try again.")


print('Name', val)

你是通过'a‘循环的，但应该是RNA。阅读评论以了解其他变化..。