swagger 2.6.1 /swagger-resources/配置/ui 404

Question

我试图将Swagger添加到中，但是我得到了一个404错误。

我的项目设置Spring4.2.5+SpringSecurity4.2.3

pom.xml

<!-- Swagger2 -->
<dependency>
    <groupId>io.springfox</groupId>
    <artifactId>springfox-swagger2</artifactId>
    <version>2.6.1</version>
</dependency>

<!-- Swagger-UI -->
<dependency>
    <groupId>io.springfox</groupId>
    <artifactId>springfox-swagger-ui</artifactId>
    <version>2.6.1</version>
</dependency>

SwaggerConfig.java

import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.ComponentScan;
import org.springframework.context.annotation.Configuration;
import org.springframework.web.servlet.config.annotation.ResourceHandlerRegistry;
import org.springframework.web.servlet.config.annotation.WebMvcConfigurationSupport;

import springfox.documentation.builders.PathSelectors;
import springfox.documentation.builders.RequestHandlerSelectors;
import springfox.documentation.service.ApiInfo;
import springfox.documentation.spi.DocumentationType;
import springfox.documentation.spring.web.plugins.Docket;
import springfox.documentation.swagger2.annotations.EnableSwagger2;

@Configuration 
@EnableSwagger2
public class SwaggerConfig extends WebMvcConfigurationSupport { 
    @Bean public Docket api() { 
        return new Docket(DocumentationType.SWAGGER_2) 
                .select() 
                .apis(RequestHandlerSelectors.any()) 
                .paths(PathSelectors.any()) 
                .build() 
                .apiInfo(apiInfo()) 
                .useDefaultResponseMessages(false); 
    }
    /** API Info */ 
    private ApiInfo apiInfo() { 
        ApiInfo apiInfo = new ApiInfo("Swagger Sample", "APIs Sample", "Sample Doc 0.1v", "", "Author Name", "This sentence will be display.", "/"); 
        return apiInfo; 
    } 

    /** Swagger UI 를 Resource Handler 에 등록 */ 
    @Override 
    public void addResourceHandlers(ResourceHandlerRegistry registry) { 
        registry.addResourceHandler("swagger-ui.html") .addResourceLocations("classpath:/META-INF/resources/"); 
        registry.addResourceHandler("/webjars/**") .addResourceLocations("classpath:/META-INF/resources/webjars/"); 
    } 

}

context-security.xml

<intercept-url pattern="/swagger-ui.html" />
<intercept-url pattern="/swagger-resources" />
<intercept-url pattern="/webjars/** " />
<intercept-url pattern="/v2/api-docs" />

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请帮帮我。

Answer 1

我希望这能帮到你。我使用Spring，swagger2，而不使用security。

将配置分为2部分

 @Configuration
    @EnableSwagger2
    @ComponentScan("com.demo.controller")
    public class SwaggerConfig{

        @Bean
        public Docket apiSwagger(){
            return new Docket(DocumentationType.SWAGGER_2)
                    .select()
                    .apis(RequestHandlerSelectors.any())
                    .paths(PathSelectors.any())
                    .build();
        }

    }

接下来，我将创建另一类配置。

@Configuration
@EnableWebMvc
@Import(SwaggerConfig.class)
public class AppSwaggerConfig extends WebMvcConfigurerAdapter {

   @Override
    public void addResourceHandlers(ResourceHandlerRegistry registry) {
        //enabling swagger-ui part for visual documentation
        registry.addResourceHandler("swagger-ui.html").addResourceLocations("classpath:/META-INF/resources/");
        registry.addResourceHandler("/webjars/**").addResourceLocations("classpath:/META-INF/resources/webjars/");
    }

}

最后，在我的WebAppInitializer类中，在Dispatcher中添加AppSwaggerConfig类

public class WebAppInitializer implements WebApplicationInitializer {

    @Override
    public void onStartup(ServletContext container) throws ServletException {

        // Create the 'root' Spring application context
        AnnotationConfigWebApplicationContext rootContext = new AnnotationConfigWebApplicationContext();
        rootContext.register(SwaggerConfig.class);

        // Manage the lifecycle of the root application context
        container.addListener(new ContextLoaderListener(rootContext));

        try {
            loadProperties(rootContext);
        } catch (IOException e) {
            throw new ServletException("Properties could not be loaded", e);
        }

        // Create the dispatcher servlet's Spring application context
        AnnotationConfigWebApplicationContext dispatcherServlet = new AnnotationConfigWebApplicationContext();
        dispatcherServlet.register(AppSwaggerConfig.class);

        // Register and map the dispatcher servlet
        ServletRegistration.Dynamic dispatcher = container.addServlet("dispatcher",
                new DispatcherServlet(dispatcherServlet));
        dispatcher.setLoadOnStartup(1);
        dispatcher.addMapping("/");
    }

Answer 2

看来，新的待办事项也需要定义几个参数。在我以前的项目中：

@Bean
public Docket configSwaggerApi() {
    return new Docket(DocumentationType.SWAGGER_2)
        .useDefaultResponseMessages(false)
        .apiInfo(new ApiInfo(environment.getProperty("api.title"), environment.getProperty("api.description"), environment.getProperty("api.version"),
                environment.getProperty("api.terms"), new Contact(environment.getProperty("api.contact.name"), environment.getProperty("api.contact.url"),
                environment.getProperty("api.contact.mail")), environment.getProperty("api.license"), environment.getProperty("api.license.url")))
        .host(environment.getProperty("platform.url"))
        .pathMapping(environment.getProperty("server.context-path"))
        .protocols(newHashSet("http", "https"))
        .produces(Arrays.stream(new String[] {"application/json"}).collect(Collectors.toSet()))
        .tags(new Tag("public", "public tools"), new Tag("user","user tools"));
}

如果使用Security，请不要忘记提供对swagger的非安全访问：

@Override
public void configure(WebSecurity web) throws Exception {
    web.ignoring().antMatchers("/favicon.ico", "/swagger*", "/swagger.json", "/swagger-resources/**", "/swagger-*/**", "/webjars/**");
}

默认路径/v2/api-docs不需要任何拦截器和配置。如果要更改它，请添加到application.properties新参数springfox.documentation.swagger.v2.path=/new/path中。

如果不使用Spring，则使用资源处理程序。

如果这些建议对您没有帮助，我可以用oauth安全访问来描述完全可行的版本。