我试图计算我的电子邮件持续时间。我有按ID分组的电子邮件。在这个示例中,我已经将我的电子邮件按组A分组了。我希望计算A组的电子邮件读取时间。我正在使用的代码计算它的最后一次和第一次(以秒为单位)。
data <-rawdata %>%
group_by(ID) %>%
summarize(diff = difftime(last(as.POSIXct(Endtime, format ="%m/%d/%Y %I:%M:%S %p")),
first(as.POSIXct(Starttime, format = "%m/%d/%Y %I:%M:%S %p" )), units = "secs"))然而,我不认为这是一个准确的显示我的电子邮件阅读。总的来说,我希望通过每一行的时差来进行更准确的阅读。所需的输出将是(以下),因为它显示了每一行的时间差,允许我进一步加总整个diff列,以确定我的电子邮件持续时间(秒)。
Starttime Endtime ID diff
12/18/2019 4:06:59PM 12/18/2019 4:07:05 PM A 6 secs
12/18/2019 4:07:26PM 12/18/2019 4:07:28 PM A 1 secs
12/17/2019 6:48:06PM 12/17/2019 6:48:07PM A 1 sec
12/17/2019 6:25:16PM 12/17/2019 6:25:22PM A 6 secs任何帮助都是非常感谢的。我会继续研究这个!
发布于 2019-12-31 00:24:27
如果您希望电子邮件的开始时间和结束时间之间的差异,您可以这样做。
library(dplyr)
rawdata %>%
mutate_at(vars(ends_with('time')), lubridate::mdy_hms) %>%
mutate(diff = difftime(Endtime, Starttime, units = "secs"))
# Starttime Endtime ID diff
#1 2019-12-18 16:06:59 2019-12-18 16:07:05 A 6 secs
#2 2019-12-18 16:07:26 2019-12-18 16:07:28 A 2 secs
#3 2019-12-17 18:48:06 2019-12-17 18:48:07 A 1 secs
#4 2019-12-17 18:25:16 2019-12-17 18:25:22 A 6 secs或在R基:
transform(transform(rawdata,
Starttime = as.POSIXct(Starttime, format = "%m/%d/%Y %I:%M:%S %p"),
Endtime = as.POSIXct(Endtime, format = "%m/%d/%Y %I:%M:%S %p")),
diff = difftime(Endtime, Starttime, units = "secs"))数据
rawdata <- structure(list(Starttime = structure(c(3L, 4L, 2L, 1L),
.Label = c("12/17/2019 6:25:16PM", "12/17/2019 6:48:06PM", "12/18/2019 4:06:59PM",
"12/18/2019 4:07:26PM"), class = "factor"), Endtime = structure(c(3L, 4L, 2L, 1L),
.Label = c("12/17/2019 6:25:22PM", "12/17/2019 6:48:07PM", "12/18/2019 4:07:05 PM",
"12/18/2019 4:07:28 PM"), class = "factor"), ID = structure(c(1L, 1L, 1L, 1L),
.Label = "A", class = "factor")), row.names = c(NA, -4L), class = "data.frame")https://stackoverflow.com/questions/59538226
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