我有一个filter()函数,它在tibble中过滤特定的Regex。因为我需要这样做不止一次,所以我想编写一个as_mapper()函数,最后得到更短的代码。我该怎么做?
我尝试了以下几点:
adverts <- as_mapper(~!grepl("(xtm)|((k|K)(i|I|1|11)(d|D)(n|N).)|(Ar<e)\\s(you)\\s(in)|
(LOAN)|(AR(\\s|\\S)[0-9])|((B|b)(i|1|l)tc.)|(Coupon)|(Plastic.King)|(organs)|(SILI)|(Electric.Cigarette.Machine)",.$value,perl = T)%>% filter)如果我试图将这个函数添加到tibble中,R会抛出一个C stack usage x is too close to the limit错误。我怎么才能避免这种情况?
可以使用以下代码生成我想要检查的tibble之一:
library(tidyverse)
library(rvest)
library(textreadr)
bribe <- read_html(paste("http://ipaidabribe.com/reports/paid?page", 10, sep = "="))
all.nodes <- c(".heading-3 a",".paid-amount span", ".date", ".location", ".transaction a")
test <- map(all.nodes, ~ html_nodes(bribe, .x) %>% html_text()) %>%
unlist %>%
as_tibble
adverts(test)发布于 2020-01-17 10:44:27
编辑以获得较短的代码
您可以编写一个不依赖于as_mapper的简单单行函数:
target_regex <- "(xtm)|((k|K)(i|I|1|11)(d|D)(n|N).)|(Ar<e)\\s(you)\\s(in)|
(LOAN)|(AR(\\s|\\S)[0-9])|((B|b)(i|1|l)tc.)|(Coupon)|(Plastic.King)|(organs)|(SILI)|(Electric.Cigarette.Machine)"
adverts <- function(df, col) df[!grepl(target_regex, df[[col]],perl = T), ]
test_df %>% adverts(col = "value")这将只返回未找到regex的df行。
我不认为您需要在这里使用映射器,您可以简单地构建一个正常的函数,它将接受一个tibble、一个目标regex作为输入,并通过一个提供grepl结果的新增列来返回该数据。一种可能是:
filter_regex <- function(df, regex, col){
df %>%
mutate(found = grepl(pattern = regex, x = df[[col]])) %>%
filter(found == TRUE) %>%
select(-found)
}
test_df <- map(all.nodes, ~ html_nodes(bribe, .x) %>% html_text()) %>%
unlist %>%
as_tibble
target_regex <- "(xtm)|((k|K)(i|I|1|11)(d|D)(n|N).)|(Ar<e)\\s(you)\\s(in)|
(LOAN)|(AR(\\s|\\S)[0-9])|((B|b)(i|1|l)tc.)|(Coupon)|(Plastic.King)|(organs)|(SILI)|(Electric.Cigarette.Machine)"
filter_regex(test_df, target_regex, "value")
> # A tibble: 7 x 1
> value
> <chr>
> 1 "\r\n Kidney Donor Needed Urgently Needed\r\n "
> 2 "\r\n Kidney Donor Needed Urgetly \r\n "
> 3 "\r\n Urgent Kidney Donor Needed\r\n "
> 4 "\r\n Urgent Kidney Donor Needed\r\n "
> 5 "\r\n Kidney Donor Needed\r\n "
> 6 "\r\n Kidney Donor Needed\r\n "
> 7 "\r\n Kidney donation urgently needed in India for 7 CR\r\n https://stackoverflow.com/questions/59784948
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