使用数组和随机的抽奖java问题

Question

所以我坚持这个程序，生成6个整数，介于1-49之间，然后将它们存储在一个数组中，并按升序显示它们，但它们必须是唯一的数字。在此之后，程序必须要求用户提供他们的6个数字，然后将随机数组与用户进行比较，以确定是否有3次或更多的匹配，从而提示他们中了彩票(假设他们输入了唯一的数字)。我必须包括一个名为checkTicket的方法，它要求用户提供他们的数字，并返回与随机数匹配的数目。顺便说一句，我对java非常陌生，所以请原谅我的编码技巧。我似乎不知道如何将随机数组与checkTicket方法中的用户数组进行比较，并计算相同的数量。这就是我到目前为止所拥有的。

import java.util.*; 
public class lottery
{ 
    public static void main (String [] args) {
        Random rand = new Random ();  
        int [] lotto= new int [6];
        int count=0;
        checkTicket(lotto, count); 
        int num =0; 


        for (int i = 0; i < 6; i++) {
            num = (int) (Math.random() * 49 + 1); 
            for ( int j  = 0; j < i; j++) {
                if (lotto[j] == num) 
                {
                    num = (int) (Math.random() * 49 + 1);
                }
            }
            lotto[i] = num;
        } 

        System.out.println("\n The lottery numbers:");
        System.out.println("\n--------------");
        for (int i=0; i< lotto.length; i++){
            System.out.print("\n"+lotto[i]);
        }
        System.out.println("\n--------------");

        if (count>3){
             System.out.println("\nYou have the winning ticket and this was the number of matches: " 
                +count);
        }
        else 
            System.out.println("\nBetter luck next time! This was how many you got right: "+count);
    }

    public static int checkTicket (int [] lotto, int count){
        System.out.println("Enter 6 numbers between 1 to 49");
        Scanner kb = new Scanner (System.in);
        count=0; 
        int [] user =new int [6];

        for ( int i=0;i<user.length;i++) 
        {
            System.out.println("Number: ");

            user[i]= kb.nextInt(); 
            System.out.println(user[i]+" ");

            for (int j= 0; j<lotto.length; j++){
                if (user[i] == lotto[j])
                    count++;

            }
        }
        return count; 
    }
}

Answer 1

我在您的代码中可以看到以下几个问题：

在将checkTicket.

• Passing count调用为checkTicket之前，需要初始化lotto数组的

1. 没有任何用处，因为您正在使用以下语句( count=0; it checkTicket)再次初始化它

这样做如下：

import java.util.Random;
import java.util.Scanner;

public class lottery {
    public static void main(String[] args) {
        Random rand = new Random();
        int[] lotto = new int[6];
        int num;
        for (int i = 0; i < 6; i++) {
            num = (int) (Math.random() * 49 + 1);
            for (int j = 0; j < i; j++) {
                if (lotto[j] == num) {
                    num = (int) (Math.random() * 49 + 1);
                }
            }
            lotto[i] = num;
        }
        int count = checkTicket(lotto);
        System.out.println("The lottery numbers:");
        System.out.println("--------------");
        for (int i = 0; i < lotto.length; i++) {
            System.out.print(lotto[i] + " ");
        }
        System.out.println("\n--------------");

        if (count > 3) {
            System.out.println("You have the winning ticket and this was the number of matches: " + count);
        } else
            System.out.println("Better luck next time! This was how many you got right: " + count);
    }

    public static int checkTicket(int[] lotto) {
        System.out.println("Enter 6 numbers between 1 to 49");
        Scanner kb = new Scanner(System.in);
        int count = 0;
        int[] user = new int[6];

        for (int i = 0; i < user.length; i++) {
            System.out.print("Number: ");
            user[i] = kb.nextInt();
            for (int j = 0; j < lotto.length; j++) {
                if (user[i] == lotto[j])
                    count++;
            }
        }
        return count;
    }
}

示例运行：

Enter 6 numbers between 1 to 49
Number: 10
Number: 20
Number: 30
Number: 40
Number: 15
Number: 25
The lottery numbers:
--------------
15 38 10 27 13 30 
--------------
Better luck next time! This was how many you got right: 3

Answer 2

在初始化lotto数组之前，您似乎正在调用checkTicket。