NoReverseMatch /account/登录/

Question

我试图找出Django默认的auth，当我使用正确的凭据登录时，它会给我这个错误

NoReverseMatch at /account/login/
Reverse for 'dashboard' not found. 'dashboard' is not a valid view function or pattern name.
Request Method: POST
Request URL:    http://127.0.0.1:8000/account/login/
Django Version: 2.2
Exception Type: NoReverseMatch
Exception Value:    
Reverse for 'dashboard' not found. 'dashboard' is not a valid view function or pattern name.
Exception Location: C:\Users\nouma\Desktop\social_website\myenv\lib\site-packages\django\urls\resolvers.py in _reverse_with_prefix, line 660

我见过一些类似的问题，但不明白我的问题到底是什么。我混淆了reverse 的概念。这是我的views.py

from django.shortcuts import render
from django.http import HttpResponse
from django.contrib.auth import authenticate, login
from .forms import LoginForm
from django.contrib.auth.decorators import login_required
# Create your views here.

def user_login(request):
    if request.method == 'POST':
        form = LoginForm(data=request.POST)
        if form.is_valid():
            cd = form.cleaned_data
            user = authenticate(request, username=cd['username'], password=cd['password'])

            if user is not None:
                if user.is_active:
                    login(request, user)
                    return HttpResponse('Authenticated successfully')
                else:
                    return HttpResponse('Disabled account')
            else:
                return HttpResponse('Invalid login')
    else:
        form = LoginForm()
    return render(request, 'account/login.html', {'form': form})

@login_required
def dashboard(request):
    return render(request, 'account/dashboard.html', {'section': 'dashboard'})

这是我的主要项目urls.py

from django.contrib import admin
from django.urls import path, include

urlpatterns = [
    path('admin/', admin.site.urls),
    path('account/', include('django.contrib.auth.urls')),
    path('account/', include('account.urls', namespace='account')),
]

应用程序的urls.py，名为account

from django.urls import path
from . import views
from django.contrib.auth import views as auth_views

app_name = 'account'

urlpatterns = [
    # login view
    # path('login/', views.user_login, name='user_login'),

    path('login/', auth_views.LoginView.as_view(), name='login'),
    path('logout/', auth_views.LogoutView.as_view(), name='logout'),
    path('', views.dashboard, name='dashboard'),
]

我的dasboard.html

{% extends 'base.html' %}

{% block title %}Dashboard{% endblock %}

{% block content %}
  <h1>Dashboard</h1>
  <p>Welcome to your dashboard</p>
{% endblock %}

login.html

{% extends "base.html" %}

{% block title %}Log-in{% endblock %}

{% block content %}
  <h1>Log-in</h1>
  {% if form.errors %}
    <p>Your username or password didn't match. Please try again</p>
  {% else %}
    <p>Please, use the following form to log-in:</p>
  {% endif %}
  <div class="login-form">
    <form action="{% url 'login' %}" method="POST">
      {{ form.as_p }}
      {% csrf_token %}
      <input type="hidden" name="next" value="{{ next }}" />
      <p><input type="submit" value="Log-in"></p>
    </form>
  </div>
{% endblock %}

我认为这个问题很小，但我无法配置。

Answer 1

您已经创建了一个自定义应用程序account，您没有在app/urls.py文件中为其定义url。

您可以添加帐户url，如

urlpatterns = [
  path('account/', include('django.contrib.auth.urls')),
  path('account/', include('account.urls', namespace='account'))
]

现在，您可以为account应用程序中定义的urls创建反向urls。

编辑2

另外，由于您已经在django.contrib.auth文件中定义了account/urls.py视图，所以不需要在app/urls.py文件中添加django.contrib.auth.urls的url。

LOGIN_REDIRECT_URL

根据文档，它接受path或named url模式。

建议的方法是使用path。对于named用法，您可以尝试使用以下方法

LOGIN_REDIRECT_URL = 'account:login'
LOGIN_REDIRECT_URL = reverse('account:login')

我不确定上述哪一种会有效，让我知道哪一种适合你。