检查字符串是否包含完全匹配的

Question

我想检查字符串(let entry)是否包含与let expect完全匹配的字符串。

​

let expect = 'i was sent'
let entry = 'i was sente to earth' // should return false
// let entry = 'to earth i was sent' should return true

// includes() using the first instance of the entry returns true
if(entry.includes(expect)){
console.log('exact match')

} else {
console.log('no matches')

}

​

在StackOverflow上有很多答案，但我找不到一个可行的解决方案。

注：

let expect = 'i was sent' 
let entry = 'to earth i was sent'

应该返回true

let expect = 'i was sent' 
let entry = 'i was sente to earth'

应该返回假

Answer 1

似乎您正在讨论匹配的单词边界，这可以在与单词边界匹配的RegExp中使用RegExp断言来完成，因此可以这样做：

​

const escapeRegExpMatch = function(s) {
    return s.replace(/[-\/\\^$*+?.()|[\]{}]/g, '\\$&');
};
const isExactMatch = (str, match) => {
  return new RegExp(`\\b${escapeRegExpMatch(match)}\\b`).test(str)
}

const expect = 'i was sent'

console.log(isExactMatch('i was sente to earth', expect)) // <~ false
console.log(isExactMatch('to earth i was sent', expect)) // <~ true

​

希望它有帮助:)

Answer 2

我还没有对此进行测试，但您需要将预期的字符串转换为字符串数组，然后检查条目字符串中是否包含所有项。

let arr = expect.split(" ");
if (arr.every(item => entry.includes(item)) {
  console.log("match");
}
else.....