Promise.all是如何在ramda管道中使用的?我想我漏掉了一些愚蠢的东西。
const pipeline: Function = R.pipe(
R.map((record) => record.body),
R.map(JSON.parse),
R.map(asyncFunction),
console.log
);返回承诺数组(Promise.all的输入)
[ Promise { <pending> },
Promise { <pending> },
Promise { <pending> },
Promise { <pending> },
Promise { <pending> },
Promise { <pending> },
Promise { <pending> },
Promise { <pending> },
Promise { <pending> },
Promise { <pending> } ]但是,如果我试图等待Promise.all解决这些承诺,如下所示:
const pipeline: Function = R.pipe(
R.map((record) => record.body),
R.map(JSON.parse),
R.map(asyncFunction),
Promise.all,
R.andThen(useTheReturn)
);最后出现一个类型错误,说明我试图使用Promise.all作为构造函数类型。
{
"errorType": "TypeError",
"errorMessage": "#<Object> is not a constructor",
"stack": [
"TypeError: #<Object> is not a constructor",
" at all (<anonymous>)",
" at /var/task/node_modules/ramda/src/internal/_pipe.js:3:14",
" at /var/task/node_modules/ramda/src/internal/_arity.js:11:19",
" at Runtime.exports.handler (/var/task/lambda/data-pipeline/1-call-summary-ingestion/index.js:14:19)",
" at Runtime.handleOnce (/var/runtime/Runtime.js:66:25)"
]
}发布于 2020-02-28 06:41:20
您需要将Promise.all绑定到Promise
const pipeline: Function = R.pipe(
R.map((record) => record.body),
R.map(JSON.parse),
R.map(asyncFunction),
R.bind(Promise.all, Promise),
R.andThen(useTheReturn)
);演示:
const pipeline = R.pipe(
R.bind(Promise.all, Promise),
R.andThen(R.sum)
);
const promise1 = Promise.resolve(10)
const promise2 = 20
const promise3 = new Promise((resolve) => setTimeout(resolve, 100, 30))
const result = pipeline([promise1, promise2, promise3])
result.then(console.log)<script src="https://cdnjs.cloudflare.com/ajax/libs/ramda/0.27.0/ramda.js"></script>
发布于 2020-05-20 08:34:16
我编写了一个名为红宝石的库,它简化了这一点,因为您不需要担心绑定承诺,也不需要自己使用Promise.all。
import { pipe, map } from 'rubico'
const pipeline: Function = pipe([
map((record) => record.body),
map(JSON.parse),
map(asyncFunction),
console.log,
]);pipe类似于ramda的管道,因为它将函数链在一起,但是在异步函数的情况下,它将在将值传递给下一个函数之前解析返回的承诺。
map就像ramda的映射,但它只适用于异步函数。
https://stackoverflow.com/questions/60446102
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