如何将输入的第二个或第三个单词附加到字典中

Question

我正在使用Python

，这是我尝试过的代码：

PIKACHU = {}
command = input("Command: ")
if "Capture" in command:
  command = command.split(' ')
  command.append[1]
if "Query" in command:
  command = command.split(' ')

print(PIKACHU[2])

我想要发生的事情的例子：

 - Command: Capture Pikachu 6
Command: Query Pikachu
Pikachu is level 6.
Command: Query Pikachu
Pikachu is level 6.
Command: Query Eevee
You have not captured Eevee yet.
Command: 

另一个例子：

- Command: Capture Eevee 4
Command: Query Eevee
Eevee is level 4.
Command: Capture Eevee 6
You are already training Eevee!
Command: 

另一个例子：

- Command: Capture Froakie 12
Command: Battle Froakie
Unknown command!
Command: Feed Froakie 5
Unknown command!
Command: Query Froakie
Froakie is level 12.

命令：

我对字典非常陌生，所以我发现很难知道如何把输入中的某些单词添加到字典中。还是名单可能更好？

提前谢谢你。我很困惑。:)

Answer 1

不确定我是否正确地理解了你的问题。根据你的例子，这是我认为你想要做的事情。

输入-If命令字符串，将口袋妖怪和级别存储在字典中

输入-If查询字符串，输出带有口袋妖怪名称和级别的字符串。

以下是你如何做到这一点：

Pokemon = {}
command = input("Command: ")
if "Capture" in command:
    command = command.split(' ')
    Pokemon[command[1]] = command[2]
    #stores Pokemon name as key and level as value

if "Query" in command:
     command = command.split(' ')
     if command[1] not in Pokemon: #checks if pokemon is not in dictionary
         print("You have not captured" +  command[1] + "yet.")
     else:
         print(command[1] "is level " + Pokemon[command[1]]) 
         #prints pokemon name and level, which is gotten from dictionary

字典就像哈希映射一样，有一个键值对。因此，这里我创建了一个字典名pokemon，并将pokemon的名称存储为键，级别存储为值。

具有多个同名的口袋妖怪：

Pokemon = {}
command = input("Command: ")
if "Capture" in command:
    command = command.split(' ')
    if command[1] not in Pokemon:
        Pokemon[command[1]] = [command[2]] 
        #if pokemon does not exist in dict yet
        #create new list with first pokemon and store its level
    else:
        Pokemon[command[1]].append(command[2])
        #appends the list value at the pokemon name with the 
        #new pokemon's level

if "Query" in command: 
     command = command.split(' ')
     if command[1] not in Pokemon: #checks if pokemon is not in dictionary
         print("You have not captured" +  command[1] + "yet.")
     else:
         print(command[1] "is level " + Pokemon[command[1]]) 
         #will print a list of pokemon
         #Example: Eevee is level [2,3,5]
         #If you want to specify which pokemon, enter index of list in 
         #Query and get pokemon through it.