我在用java Mapstruct。与gradle bootRun一起运行是正常的,但是VSCode在调试和运行单元测试时遇到了一些问题:java.lang.ClassNotFoundException: Cannot find implementation。
信息: IDE VSCode,SpringBoot 2.2.2,Java 11,Gradle 6.1.1
build.gradle:
compileJava {
options.compilerArgs = [
'-Amapstruct.defaultComponentModel=spring'
]
}
dependencies {
implementation 'org.mapstruct:mapstruct-jdk8:1.3.1.Final'
implementation 'org.mapstruct:mapstruct-processor:1.3.1.Final'
annotationProcessor 'org.mapstruct:mapstruct-processor:1.3.1.Final'
testAnnotationProcessor 'org.mapstruct:mapstruct-processor:1.3.1.Final'
}launch.json用于在VSCode中进行调试:
{
"type": "java",
"name": "Debug (Launch)-DemoApplication<demo>",
"request": "launch",
"mainClass": "com.api.demo.DemoApplication",
"projectName": "demo",
"args": [
"-Amapstruct.defaultComponentModel=spring",
"-DprocessorIntegrationTest.debug=true",
"-classpath",
"${workspaceFolder}/build/classes/"
],
"sourcePaths": [
"${workspaceFolder}/build/generated/"
]
}Mapper文件:
@Mapper(componentModel = "spring", unmappedTargetPolicy = ReportingPolicy.IGNORE)
public interface UserPayloadMapper extends GenericPayloadMapper<User, UserRegistryRequest, UserRegistryResponse> {
UserPayloadMapper INSTANCE = Mappers.getMapper(UserPayloadMapper.class);
@Mapping(source = "userId", target = "id")
public User fromRequest(UserRegistryRequest request);
public UserRegistryResponse toResponse(User user);
}有人能帮我配置VSCode来运行调试和单元测试吗?我认为在运行调试和单元测试之前,它不会加载生成的源代码,但我不知道如何修复它。
编辑:对于单元测试文件,如果我添加@SpringBootTest(classes = { UserPayloadMapper.class }),这将正确运行,但是在单元测试代码中与此映射程序无关,而且我有几个映射器,我不能将它们全部放入每个单元测试中。
发布于 2020-03-23 09:51:33
我找到了解决方案:添加@ComponentScan(basePackages = "com.api.demo/build/classes/java/main/com/api/demo/service/mapper")并工作(到mapstruct生成的文件夹)。
发布于 2021-08-02 18:13:02
build.gradle的依赖关系
dependencies {
compile group: 'org.mapstruct', name: 'mapstruct-jdk8', version: '1.2.0.Final'
annotationProcessor 'org.mapstruct:mapstruct-processor:1.2.0.Final'
}从Dto映射到模型的接口
@Mapper(unmappedTargetPolicy = ReportingPolicy.IGNORE)
public interface Mapper {
DatabaseDto toModel(ModelDto source);
// Converting DatabaseDto to ModelDto based on the matched Columns
// Mappings with Different Column names from Source to Destination
@Mappings({
@Mapping(target="id", source="dto.employeeId"),
@Mapping(target="name", source="dto.employeeName")
})
ModelDto fromModel(DatabaseDto dto);
}https://stackoverflow.com/questions/60809894
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