逐行读取并替换字符串递归

Question

我有一个文件，其中包含多个lines.Here示例

etc/list.txt

MLA1234,MLA2345
MLA1235,MLA2345

我需要在文件夹中搜索递归，搜索这个字符串和remplace。示例

etc/json/other/file2.json

{id:"MLA1234" , product_name:"blablabla"

取代string MLA1234的预期前哨

etc/json/其他/file2.json(最终)

{id:"MLA2345" , product_name:"blablabla"

我做了这样的事，但没有对手

#!/bin/bash

csvfile='list.txt'

# Make sure the file exists
if [ ! -f $csvfile ]
then
    echo "ERROR: file $csvfile does not exist."
    exit 1
fi

# Read the input file line per line
while read line
do

 # Capture the information out of the line, fields separated by ;
    IFS=',' read old new <<< $line



grep -rl $old . | xargs sed -i "s/$oldstring/$new/g"

Answer 1

他为我工作！我修好密码了！

#!/bin/bash

csvfile='list.txt'

# Make sure the file exists
if [ ! -f $csvfile ]
then
    echo "ERROR: file $csvfile does not exist."
    exit 1
fi

# Read the input file line per line
sed '1d' $csvfile | while read line
do
    # Capture the information out of the line, fields separated by ;
    IFS=',' read new old  <<< $line


grep -rl "$old" . | xargs sed -i "s/$old/$new/g"


done```