我试图使用Python中的ElementTree XML解析下面的XML格式,但是当我使用.text时,它会给出属性错误。
<address-group>
<entry name="TBR">
<static>
<member>TBR1-1.1.1.1_21</member>
<member>TBR2-2.2.2.2_24</member>
<member>TBR3-3.3.3.3_21</member>
<member>TBR4-4.4.4.4_24</member>
</static>
</entry>
<address-group>这是我的代码:
import xml.etree.ElementTree as ET
tree = ET.parse("addrgrp.xml")
root = tree.getroot()
tag = root.tag
print (tag)
attr = root.attrib
for entries in root.findall("entry"):
name = entries.get('name')
print (name)
ip = entries.find('static')
print (ip)
for mem in ip.findall('member'):
member = mem.find('member')
print (member)发布于 2020-03-31 14:13:09
下面的代码按条目名称聚合每个条目的成员。
import xml.etree.ElementTree as ET
import pprint
XML = '''
<address-group>
<entry name="TBR1">
<static>
<member>TBR1-1.1.1.1_21</member>
<member>TBR2-2.2.2.2_24</member>
<member>TBR3-3.3.3.3_21</member>
<member>TBR4-4.4.4.4_24</member>
</static>
</entry>
<entry name="TBR2">
<static>
<member>TBR1-4.1.1.1_21</member>
<member>TBR2-4.2.2.2_24</member>
<member>TBR3-4.3.3.3_21</member>
<member>TBR4-9.4.4.4_24</member>
</static>
</entry>
</address-group>'''
root = ET.fromstring(XML)
data_by_entry = {}
entries = root.findall('.//entry')
for entry in entries:
data_by_entry[entry.attrib['name']] = [m.text for m in entry.findall('./static/member')]
pprint.pprint(data_by_entry)输出
{'TBR1': ['TBR1-1.1.1.1_21',
'TBR2-2.2.2.2_24',
'TBR3-3.3.3.3_21',
'TBR4-4.4.4.4_24'],
'TBR2': ['TBR1-4.1.1.1_21',
'TBR2-4.2.2.2_24',
'TBR3-4.3.3.3_21',
'TBR4-9.4.4.4_24']}发布于 2020-04-08 08:10:39
你问题的根源是:
for mem in ip.findall('member'):循环mem是当前的成员元素member = mem.find('member'),所以您尝试在当前成员中找到另一个(嵌套)成员,该成员不存在。代码中的另一个缺陷是,打印没有任何文本的节点是没有意义的。
将循环更改为下面的代码:
for entries in root.findall('entry'):
name = entries.get('name')
print(name)
ip = entries.find('static')
print('Members:')
for mem in ip.findall('member'):
print(mem.text)你就会得到有意义的结果。
https://stackoverflow.com/questions/60952029
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