如果第二个元素值不是空的,我将尝试使用XSLT并将xml元素值替换为另一个元素。在下面的示例中,只有在项目标签值存在的情况下,我才需要用ItemMaster-CustomChar10标记值替换项目标记值。
<WmsShippingResultOutSiEs>
<RecordId>6</RecordId>
<ShipmentTransactionId>146</ShipmentTransactionId>
<OutboundOrder>ERIC_1</OutboundOrder>
<WmsShippingResultLineOutSiEs>
<Line>
<RecordId>6</RecordId>
<ShipmentLineSequence>1</ShipmentLineSequence>
<Item>BMS9</Item>
<ItemMaster-CustomChar10>BMS9ALIAS</ItemMaster-CustomChar10>
<WmsShippingResultLineDetailOutSiEs>
<Line>
<ShipmentLineSequence>1</ShipmentLineSequence>
<ShipmentLineDetailTransactionId>143</ShipmentLineDetailTransactionId>
</Line>
</WmsShippingResultLineDetailOutSiEs>
</Line>
<Line>
<RecordId>6</RecordId>
<ShipmentLineSequence>2</ShipmentLineSequence>
<Item>BMS10</Item>
<ItemMaster-CustomChar10/>
<WmsShippingResultLineDetailOutSiEs>
<Line>
<ShipmentLineSequence>1</ShipmentLineSequence>
<ShipmentLineDetailTransactionId>144</ShipmentLineDetailTransactionId>
</Line>
<Line>
<ShipmentLineSequence>2</ShipmentLineSequence>
<ShipmentLineDetailTransactionId>145</ShipmentLineDetailTransactionId>
</Line>
</WmsShippingResultLineDetailOutSiEs>
</Line>
</WmsShippingResultLineOutSiEs>
</WmsShippingResultOutSiEs>我希望能得到一个像
<WmsShippingResultOutSiEs>
<RecordId>6</RecordId>
<ShipmentTransactionId>146</ShipmentTransactionId>
<OutboundOrder>ERIC_1</OutboundOrder>
<WmsShippingResultLineOutSiEs>
<Line>
<RecordId>6</RecordId>
<ShipmentLineSequence>1</ShipmentLineSequence>
<Item>BMS9ALIAS</Item>
<ItemMaster-CustomChar10>BMS9ALIAS</ItemMaster-CustomChar10>
<WmsShippingResultLineDetailOutSiEs>
<Line>
<ShipmentLineSequence>1</ShipmentLineSequence>
<ShipmentLineDetailTransactionId>143</ShipmentLineDetailTransactionId>
</Line>
</WmsShippingResultLineDetailOutSiEs>
</Line>
<Line>
<RecordId>6</RecordId>
<ShipmentLineSequence>2</ShipmentLineSequence>
<Item>BMS10</Item>
<ItemMaster-CustomChar10/>
<WmsShippingResultLineDetailOutSiEs>
<Line>
<ShipmentLineSequence>1</ShipmentLineSequence>
<ShipmentLineDetailTransactionId>144</ShipmentLineDetailTransactionId>
</Line>
<Line>
<ShipmentLineSequence>2</ShipmentLineSequence>
<ShipmentLineDetailTransactionId>145</ShipmentLineDetailTransactionId>
</Line>
</WmsShippingResultLineDetailOutSiEs>
</Line>
</WmsShippingResultLineOutSiEs>
</WmsShippingResultOutSiEs>所有其他需要的元素都不应该受到影响。可以用递归的方式来做吗?
下面的XSLT代码不起作用
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes" omit-xml-declaration="no"/>
<!-- identity template -->
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:for-each select="//WmsShippingResultLineDetailOutSiEs/Lines">
<xsl:variable name="host_item" select="ItemMaster-CustomChar10"/>
<xsl:if test="ItemMaster-CustomChar10 !=''">
<Item>
<xsl:value-of select="$host_item"/>
</Item>
</xsl:if>
</xsl:for-each>
非常感谢
发布于 2020-04-05 07:49:11
与大多数XML到XML转换一样,我建议使用标识转换作为起点,然后为要更改的元素添加一个模板:
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="Line[ItemMaster-CustomChar10[normalize-space()]]/Item">
<xsl:copy>
<xsl:value-of select="../ItemMaster-CustomChar10"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>https://stackoverflow.com/questions/61035503
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