为了防止im错误诊断,下面是发送内容的示例: T6NLmFUZdYYdvhxmq67WD/TiShKbE0rK0xdHXJGo5sVx9/CrmBTViiQxjqLEQN66HkAUB9LvXW6C55maPLMd7u2cwNc8OlNuPTvZfx63Aawso/2mvewXQauUytGZ1Q8D
收到了什么: T6NLmFUZdYYdvhxmq67WD%2fTiShKbE0rK0xdHXJGo5sVx9%2fCrmBTViiQxjqLEQN66HkAUB9LvXW6C55maPLMd7u2cwNc8OlNuPTvZfx63Aawso%2f2mvewXQauUytGZ1Q8D
'%2‘而不是反斜杠是我谈论的最好的例子
EDIT2给后来者:上传处理程序raw做了这个技巧,并修复了它。但是,如果希望能够访问服务器回复,则需要创建下载处理程序。对于文本,请使用DownloadHandlerBuffer,例如
www.downloadHandler = new DownloadHandlerBuffer();然后,发送请求后,使用它获得一个字符串响应:
string response = System.Text.Encoding.UTF8.GetString(www.downloadHandler.data);我使用联合的UnityWebRequest向Azure函数HttpTrigger类型功能发送REST调用。
现在,这两个函数都不公开字节,它们在后端这样做,并给我字符串。然而,当我的函数接收到我的数据时,它包含了大量转义字符,我认为它没有正确编码。我不知道如何正确地编码它,因为我不能仅仅用UTF8.GetBytes将我的字符串转换为一个byte[],而vis则相反。
抱歉,如果重复,我找不到一个类似的问题。
参见这里的统一和蔚蓝代码:https://pastebin.com/pE4dYSfF
//UNITY SIDE
IEnumerator Foo()
{
var N = JSON.Parse("{}");
N["input1"] = input1.text;
N["input2"] = input2.text;
string encrypted = Encrypt(N.ToString(), GenerateEncryptionKey);
print("ENSEND: \n" + encrypted);
using (UnityWebRequest www = UnityWebRequest.Post(targetURL, encrypted))
{
yield return www.SendWebRequest();
if (www.isHttpError || www.isNetworkError)
{
Debug.LogError(www.error + "\n" + www.downloadHandler.text);
onFail?.Invoke();
}
else
{
onSuccess?.Invoke();
print(www.responseCode + " : " + www.downloadHandler.text);
}
}
yield break;
}
//FUNCTION SIDE
[FunctionName("UserAuthentication")]
public static async Task<IActionResult> Run(
[HttpTrigger(AuthorizationLevel.Anonymous, "get", "post", Route = null)] HttpRequest req,
ILogger log)
{
log.LogInformation("C# HTTP trigger function processed a request.");
string name = req.Query["name"];
string requestBody = await new StreamReader(req.Body).ReadToEndAsync();
try
{
requestBody = Decrypt(requestBody, "Dracon");
} catch (Exception e)
{
//Throwing exception here due to escaped characters
return new BadRequestObjectResult(e.Message + "\n" + requestBody + "\n" + Regex.Unescape(requestBody));
}
JSONNode N = null;
try
{
N = JSON.Parse(requestBody);
if (N["input1"] != "")
{
name = N["username"];
return (ActionResult)new OkObjectResult($"Hello, {name}");
} else if (name != "")
{
return (ActionResult)new OkObjectResult($"Hello, {name}");
} else
{
return new BadRequestObjectResult("Invalid object syntax");
}
} catch (Exception e)
{
return new BadRequestObjectResult("Invalid JSON provided. N = " + (N != null).ToString() + "\n" + requestBody + "\n" + e.Message);
}
}发布于 2020-04-07 05:47:50
我看到在您的Unity中有一个Encrypt函数,在Azure函数侧有一个Decrypt函数。
因此,您需要知道加密的内容是否都是普通字符。如果它们是普通字符,则可以尝试将Content-Type设置为:
using (UnityWebRequest www = UnityWebRequest.Post(targetURL, encrypted))
{
www.SetRequestHeader("Content-Type", "text/plain; charset=UTF-8");
yield return www.SendWebRequest();
if (www.isHttpError || www.isNetworkError)
{
Debug.LogError(www.error + "\n" + www.downloadHandler.text);
onFail?.Invoke();
}
else
{
onSuccess?.Invoke();
print(www.responseCode + " : " + www.downloadHandler.text);
}
}www.SetRequestHeader("Content-Type", "text/plain; charset=UTF-8");将确保所有字节都以utf-8编码。
但是,如果有一些特殊的字符,我建议您将Content-Type设置为application/octet-stream。这样,Azure函数将只为您保留请求正文的所有字节。
using (UnityWebRequest www = new UnityWebRequest(url,"POST"))
{
byte[] body = Encoding.UTF8.GetBytes(encrypted);
www.uploadHandler = new UploadHandlerRaw(body);
www.SetRequestHeader("Content-Type", "text/plain; charset=UTF-8");
yield return www.SendWebRequest();
if (www.isHttpError || www.isNetworkError)
{
Debug.LogError(www.error + "\n" + www.downloadHandler.text);
onFail?.Invoke();
}
else
{
onSuccess?.Invoke();
print(www.responseCode + " : " + www.downloadHandler.text);
}
}https://stackoverflow.com/questions/61071563
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